Given:
price = 1,250
sales discount = 15%
sales tax = 6.5%
The problem is unclear whether the price is the original price or the discounted price. I am assuming that the price is the original price.
Original price times sales discount rate is the value of sales discount
1,250 x 15% = 187.50
Original price less the value of sales discount is the discounted price.
1,250 - 187.50 = 1,062.50
Discounted price times sales tax rate is the value of the sales tax
1,062.50 x 6.5% = 69.06
Discounted price plus sales tax is the total cost of the purchase
1,062.50 + 69.06 = 1,131.56
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature =
= 15°c
The final temperature =
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × (
-
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Well since we already have our unit per mile.
We know that 1 mile = $3.50
And that the tow company towed the car 12 miles.
So we would have to multiply 12 by $3.50
soo..
12 x $3.50 = $42.00
So your answer is D. $42.00
Answer:
sorry but it is wrong the answer is 1,200
Step-by-step explanation: