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➷ final = original x multiplier^n
n is the number of years
Substitute in the values:
final = 20,000 x 0.875^11
final = 4603.8225
The answer would be $4603.82
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Given that the first mass of the duck is 0.05 kg and it gains weight at a rate of 0.042 kg/week, the equation that would represent this scenario is,
y = 0.05 + 0.042x
where y is weight and x is the number of weeks. To determine the number of weeks in which the duck's mass becomes 0.890,
0.890 = 0.05 + 0.042x
The value of x from the equation is 20.
Answer:
y= - 1/2 (negative half) = -0.5
Step-by-step explanation:
−6y+3(12y)=20(y−1)+15
Multiply 3 and 12 to get 36.
−6y+36y=20(y−1)+15
Combine −6y and 36y to get 30y.
30y=20(y−1)+15
Use the distributive property to multiply 20 by y−1.
30y=20y−20+15
Add −20 and 15 to get −5.
30y=20y−5
Subtract 20y from both sides.
30y−20y=−5
Combine 30y and −20y to get 10y.
10y=−5
Divide both sides by 10
y= -5/10
Reduce the fraction -5/10 = -0.5 to lowest terms by extracting and cancelling out 5 .
Answer:
<em>Mean of the sample = 27.83</em>
<em> The variance of the the sample = 106.96</em>
<em> </em><em>Standard deviation of the sample = 10.34</em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given random sample of six employees
x 26 32 29 16 45 19
mean of the sample
Mean of the given data = 27.83
<u>Step(ii):-</u>
<u>Given data</u>
x : 26 32 29 16 45 19
x - x⁻ : -1.83 4.17 1.17 -11.83 17.17 -8.83
(x - x⁻)² : 3.3489 17.3889 1.3689 139.9489 294.80 77.9689
∑ (x-x⁻)² = 534.8245
Given sample size 'n' =6
The variance of given data
S² = ∑(x-x⁻)² / n-1
The variance of the given sample = 106.9649
<u> Step(iii):-</u>
Standard deviation of the given data
Standard deviation of the sample = 10.3423
