<span> If P(x) is a polynomial with integer coefficients and if is a zero of P(x) ( P( ) = 0 ), then p is a factor of the constant term of P(x) and q is a factor of the leading coefficient of P(x) .
</span><span>A. x – 6
</span><span>60(6)^4 + 86(6)^3 – 46(6)^2 – 43(6) + 8 = 94430
</span><span>
B. 5x – 8
</span>60(8/5)^4 + 86(8/5)^3 – 46(8/5)^2 – 43(8/5) + 8 = 566.912<span>
C. 6x – 1
</span>60(1/6)^4 + 86(1/6)^3 – 46(1/6)^2 – 43(1/6) + 8 = 0 -------> ANSWER
<span>
D. 8x + 5
</span>60(-5/8)^4 + 86(-5/8)^3 – 46(-5/8)^2 – 43(-5/8) + 8 = 5.07
Revenue > Cost
R(x) > C(x)
0.50x > 10+0.20x
0.50x-0.20x > 10
0.30x > 10
x > 10/0.30
x > 33.333 which is approximate
Round up to the nearest whole number to get x = 34. You need to sell at least 34 cups of lemonade to have the revenue R(x) be larger than the cost C(x)
Answer: 34
Answer:
BC = 26
Step-by-step explanation:
Given that:
B is the midpoint of AC
Then AC = AB + BC
AC = 8x - 20 and AB = 3x - 1
Then,
8x - 20 = (3x - 1) + BC
8x - 20 - (3x - 1) = BC
8x - 20 - 3x + 1 = BC
5x - 19 = BC
But AB = BC
5x - 19 = 3x - 1
5x - 3x = - 1 + 19
2x = 18
x = 9
Hence,
Since BC = AB = 3x - 1
3(9) - 1
27 - 1
= 26
Answer:
He set the compass on a, with the width slightly wider than the distance to o and drew an arc above and below o. He then set the compass on b, without changing the width on the compass and did the same thing. True
He drew a line through where the arc pairs intersected and then labeled the points where this line crossed the top and bottom of the original circle. True
He set the compass on o, with the width slightly wider than the distance to b, and he drew a slightly larger circle around the original circle. False
He used the points that were marked along the circumference of the original circle as the vertices for the square. True
Step-by-step explanation:
Performance matters test perhaps?
<span>The area increases to 2 times the original value. </span>
