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Ksju [112]
2 years ago
6

A right rectangular prism and an oblique triangular prism are both 12 centimeters tall and have the same volume. What statement

must be true about two solids?
Mathematics
2 answers:
Bas_tet [7]2 years ago
7 0
This is the concept of volumes of solid figures, given that the height of the right rectangular prism and the oblique triangular prism are 12 cm and both prisms have the same volume, we can conclude that:
Horizontal cross-sections of the prisms at the same height have the same area.
MakcuM [25]2 years ago
5 0

Answer:

We conclude that both the prism has same area.

Step-by-step explanation:

Given a right rectangular prism and an oblique triangular prism are both 12 centimeters tall and have the same volume.

we have to conclude the correct statement about these two prism.

As, given the height of both prism are same i.e 12 cm and also have same volume implies same cross-section or we can say have same base.

and also, Horizontal cross-sections of the prisms at the same height have the same area.

We conclude that both the prism has same area.

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Horizontal plane A and vertical plane B intersect at a line. Line n is vertical on plane B and forms a right angle with horizont
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Answer:

L and M - None of these

L and N - Skew

M and N - Perpendicular

Step-by-step explanation:

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1 year ago
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In the diagram, the measurements that are labeled are known, while the other measurements are unknown. Which measurement of acut
andrew-mc [135]
As the sine rule states,

A/sina = B/sinb = C/sinc .

in the diagram, there are two identified sides and if you use the sine rule, you can find the opposed angles easily.

there are:

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side b, with angle b.

so the answer is C.

if you input these into the sine rule, it would be:

a/ sin a = b/sin b
8 0
2 years ago
A group of 5 friends decides to share the cost of a party together. If the party costs $1,100, how much does each friend pay?
seraphim [82]

Answer:

1,100 dollars divided by 5 friends is 220 dollars so each friend would have to pay 220 dollars

Step-by-step explanation:


7 0
1 year ago
There were 340,000 cattle placed on feed. Write an equivalent ratio that could be used to find how many of these cattle were bet
lutik1710 [3]

There were 340,000 cattle placed on feed

How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?

Given the fraction of total cattle for 700 - 799 pounds is 2/5

Let x be the number of cattle between 700 - 799 pounds

We make a proportion using the fraction

\frac{2}{5} = \frac{x}{340,000}

Cross multiply it and solve for x

340000* 2 = 5x

680000 = 5x

Divide by 5 on both sides

So x= 136,000

There were 136,000 cattle between 700 and 799 pounds

3 0
1 year ago
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Here are seven tiles: 1,1,3,3,3,5,5. Tom takes a tile at random. He does not replace the tile. Tom then takes a second tile. A)
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Answer:

a) 2/42

b)16/42

Step-by-step explanation:

a) 2/7 x 1/6 = 2/42

b) (1,2)  (1,3) (2,3)

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Add all = 6/42 + 4/42 + 6/42 = 16/42

4 0
1 year ago
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