981 rounded to nearest 100
1 answer:
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Answer:
Width of the uniform path that surrounds the piece of land = 3 m
Step-by-step explanation:
Let the width of the path that surrounds the piece of land be x.
The situation described is sketched in the attached image to this solution.
The dimension of the Length of the piece of land including the uniform path that surrounds it = (40 + 2x) m
The Breadth of the piece of land including the uniform path that surrounds it = (25 + 2x) m
The area of the piece of land including the uniform path that surrounds it
= (Area of the piece of land) + (Area of the uniform path that surrounds it)
Area of the piece of land = Length × Breadth = 40 × 25 = 1000 m²
Area of the uniform path that surrounds it = 426 m² (Given in the question)
The area of the piece of land including the uniform path that surrounds it = 1000 + 426 = 1426 m²
But the area of the piece of land including the uniform path that surrounds it is also
= (Length of the piece of land including the uniform path that surrounds it) × (Breadth of the piece of land including the uniform path that surrounds it
= (40 + 2x) + (25 + 2x)
= 1000 + 80x + 50x + 4x²
= (4x² + 130x + 1000) m²
Equation these 2 areas
4x² + 130x + 1000 = 1426
4x² + 130x - 426 = 0
Solving the quadratic equation
x = 3 or -35.5
Since the width cannot be negative,
x = 3 m
Hope this Helps!!!
Answer:
Step-by-step explanation:
We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have a point (8,1) and a slope from the equation y=-23x+5. We will chose point-slope since we have a point and slope.
Point slope:
in our new equation because it us perpendicular to it. This means we will need to change it into its negative reciprocal which is
.
We will substitute and
.
.
This is the equation of the line perpendicular to y=-23x+5 that crosses through (8,1).
Answer:
Step-by-step explanation:
Let's translate what you've written in words to an expression with mathematical symbols.
To solve this, you need to multiply both the numerator and denominator with the conjugate of the denominator.