If I have a stack of pennies. And I have to tell that without counting whether there are even number of pennies or odd.
Even numbers are the numbers which are divisible by 2 and odd numbers are the numbers which are not divisible by 2.
Then I will put the given pennies in 2 rows and then I will match them to form a pair of 2 pennies.
After matching, if there is 1 penny left over, then there is an odd number of pennies and if all the pennies have a match,then there is an even number of pennies.
Let r = usual driving rate
let t = usual driving time
We need to figure out t
The distance she covers in her usual time at her usual rate is r*t
The distance she covers in her new time at her new rate is:
(1+t)*((2/3)r)
Set this equal to each other and solve for t.
rt = (2/3)r + (2/3)rt
(1/3)rt = (2/3)r
(1/3)t = (2/3)
t = 2
So her usual time is 2 hours. (There's probably a faster way to do this)
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Answer:</h2>
<u>The correct option is </u><u>The letter on the front will be N. The letter on the back will be L.
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Step-by-step explanation:</h2>
When we fold the given net, we will get Q,P,M and N on sides. Side M will come to the top, side Q on the right side, side P on the left and side O on the bottom. The side which comes to the front will be N of the observer and similarly the side L will come to the back of the rectangular prism.
The hypotenuse of the way that they have taken is equal to 2 miles. Jogging this distance with a rate of 5 miles per hour will take Jesse 0.4 hours. Further, for Mark to be back to the starting point, the total distance covered is 2.75. Dividing the distance by 12 miles per hour, it will take Mark only 0.23 hours. Thus, Mark will reach the initial point first.
Answer:
106.1 ft/s
Step-by-step explanation:
You know the diagonal of a square is √2 times the length of one side, so the distance from 3rd to 1st is 90√2 feet ≈ 127.2792 ft.
The speed is the ratio of distance to time:
speed = distance/time = 127.2972 ft/(1.2 s) ≈ 106.1 ft/s.
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In case you have never figured or seen the computation of the diagonal of a square (the hypotenuse of an isosceles right triangle), consider the square with side lengths 1. The diagonal will cut the square into halves that are isosceles right triangles with leg lengths 1. Then the Pythagorean theorem can be used to find the diagonal length d:
d² = 1² + 1²
d² = 2
d = √2
Since this is the diagonal for a side length of 1, any other side length will serve as a scale factor for this value. A square with a side length of 90 ft will have a diagonal measuring 90√2 ft.
