Hello.<span><span> </span><span>
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Let 2003 be the zero year; then 2005 is the three year, and 2008 the 5 year.
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P = ab^x
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P(3) = ab^3 = 800000
P(0) = ab^0 = 900000
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a = 900000
Solve for "b"::
b^3 = 8/9
b = 2/cbrt(9)
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Equation::
P(x) = 900000^x
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Ans: P(5) = 900000
Have a nice day</span></span></span></span>
Answer:
It would be D, 62
Step-by-step explanation:
The sample size for the group with the average height is the highest, being at 40 instead of 30, 20, or 10, and therefore has the most accurate average height.
Answer: 15.7 minutes
Step-by-step explanation:
Let x be the time in the beginning (in minutes).
Given: The track team is trying to reduce their time for a relay race.
First they reduce their time by 2.1 minutes.
Then they are able to reduce that time by 10
If their final time is 3.96 minutes, then
x-t1-t2= 3.6
x= 3.6+ t1+ t2
x= 3.6+ 2.1+ 10
x= 15.7
Hence, their beginning time was 15.7 minutes.
Percent increase
find increase first
10500 to 11300
11300-10500=800
so
percent increase
change/original
origianal=10500
change=800
800/10500=8/105=0.0761
percent means parts out of 100
0.0761/1 times 100/100=7.61/100=7.61%
rond 7.61% to tenth or to 7.6%
7.6%
Answer:
The answer should be $7,087.50
Step-by-step explanation:
4.50 x 50 = 225
225 x 1.05 = 236.25
236.25 x 30 = 7087.50
