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Nina [5.8K]
2 years ago
15

If Patricia drives at two-third of her usual speed, she covers a certain distance in one hour more than the time she takes while

driving at her usual speed. The time taken by her to cover this distance with her usual speed is _____ hours.
please help me!
Mathematics
1 answer:
zalisa [80]2 years ago
3 0
Let r = usual driving rate
let t = usual driving time
We need to figure out t

The distance she covers in her usual time at her usual rate is r*t

The distance she covers in her new time at her new rate is:
(1+t)*((2/3)r)

Set this equal to each other and solve for t.

rt = (2/3)r + (2/3)rt
(1/3)rt = (2/3)r
(1/3)t = (2/3)
t = 2

So her usual time is 2 hours. (There's probably a faster way to do this)
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Radius = d/2 = 6.5/2 = 3.25 inch, ds/dt = ? can also be understood as the rate at which the surface area of the cylindrical paint can is coated.

We know that the surface area of a cylinder = 2πrh + 2πr², this is equation 1

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Dh/dt = 120/π x (3.25)²

Now differentiate the surface area equation 1

ds/dt = 2 x π x r dh/dt + 0 , where r is constant

replace the value of dh/dt in the above equation of ds/dt

ds/ dt = 2 x π x 3.25 x (120/π x (3.25)²

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Which expression could be used to determine the product of –4 and 3 and one - fourth?
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How many 5-digit numbers are there that are divisible by either 45 or 60 but are not divisible by 90?
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Answer:

2500 numbers

Step-by-step explanation:

Problem;

 Solving for the number of 5-digit numbers divisible either by 45 or 60 but not divisible by 90;

 Let us approach this in a step wise manner;

  5 -digits numbers ranges from 10,000 to 99,999

To solve this problem, let us find the number of digits that are divisible by 45;  

  the first number divisible by 45 within this range is 10035

   the last number divisible by 45 in this range is 99990

    increment is 45

The total number in this range is:

           \frac{last number - first number}{increment}  + 1  = \frac{99990 - 10035}{45}  + 1

                                                      =  2000 numbers

To solve this problem, let us find the number of digits that are divisible by 60;  

  the first number divisible by 60 within this range is 10020

   the last number divisible by  in this range is 99960

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\frac{99990 - 10080 }{90}

The total number in this range is:

               \frac{last number - first number}{increment}  + 1  = \frac{99960 - 10020}{60}  + 1  

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The total number in this range is:

         \frac{last number - first number}{increment} + 1  = \frac{99990 - 10080}{90} + 1

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Now solution:

  Number of 5 digits  = number of 45  + number of 60 - number of 90

                                       = 2000 + 1500  - 1000

                                        = 2500 numbers

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