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2 years ago

Explain how to use equivalent ratios to find 125% of 200.

2 answers:

7 0

125 of 200 can be wriiten as:
125
200
Multiply both numerator & denominator by 100

125
200
×
100
100
=
62.5
100
= 62.5%
If you are using a calculator, simply enter 125÷200×100 which will give you 62.5 as the answer.

expeople1 [14]2 years ago

3 0

Write 125% as the ratio 125/100. To find an equivalent ratio, you know that 100 times 2 = 200, so 125 x 2 will give you the answer. 125 x 2 = 250. 125% of 200 is 250.

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A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr

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Answer:

The confidence interval for the difference in proportions is

$-0.028\leq p_1-p_2 \leq 0.096$

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

$p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034$

The estimated standard error is:

$\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316$

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

$LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096$

The confidence interval for the difference in proportions is

$-0.028\leq p_1-p_2 \leq 0.096$

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

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1 year ago

Jalisa is using 5/6 yard of ribbon to make bows for her party favors. Jalisa needs to make 6 bows. What is the length of the rib

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5/36 yard. 5/6 and multiply by the reciprocal of 6, 1/6.

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1 year ago

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What is the first step in writing f(x) = 6x2 + 5 – 42x in vertex form?

Marat540 [252]

F(x) = 6x² + 5 - 42x

first step in writing the f(x) in vertex form? WRITE THE FUNCTION IN STANDARD FORM.

f(x) = 6x² - 42x + 5

Exponents must be in decreasing order.

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1 year ago

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A survey conducted five years ago by the health center at a university showed that 18% of the students smoked at the time. This

podryga [215]

Answer:

test statistic (Z) is 2.5767 and p-value of the test is .009975

Step-by-step explanation:

$H_{0}$ : percentage of students who smoke did not change

$H_{a}$ : percentage of students who smoke has changed

z-statistic for the sample proportion can be calculated as follows:

z= $\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of smoking students ( $\frac{50}{200}$ =0.25)

p is the proportion of smoking students in the survey conducted five years ago (18% or 0.18)
N is the sample size (200)

Then, z= $\frac{0.25-0.18}{\sqrt{\frac{0.18*0.82}{200} } }$ ≈ 2.5767

What is being surveyed is if the percentage of students who smoke has changed over the last five years, therefore we need to seek two tailed p-value, which is .009975.

This p value is significant at 99% confidence level. Since .009975 <α/2=0.005, there is significant evidence that the percentage of students who smoke has changed over the last five years

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