AnswER
THE SECOND ONE IS ANY WHOLE NUMBER I JUST TOOK THE QUIZ
Step-by-step explanation:
First draw 24 shapes of your choice.
Then, in a different space or below those 24 shapes, draw 10 more shapes twice. So draw 10 shapes and draw 10 more next to them. Finally, draw 4 more shapes with space between them and say "10+10+4=24"
Answer:
140 is the answer for y2 because x1 is 80 more than x2 so you would subtract y2 by 80
Hey
So my brother posted this on Yahoo
Draw a line from the center of the circle to one of the ends of the chord (water surface) and another to the point at greatest depth. A right-angled triangle is formed. Length of side to the water-surface is 5 cm, the hypot is 7 cm.
<span>What you do now is the following: </span>
<span>Calculate the angle θ in the corner of the right-angled triangle by: cos θ = 5/7 ⇒ θ = cos ˉ¹ (5/7) </span>
<span>So θ is approx 44.4°, so the angle subtended at the center of the circle by the water surface is roughly 88.8° </span>
<span>The area shaded will then be the area of the sector minus the area of the triangle above the water in your diagram. </span>
<span>Shaded area ≃ 88.8/360*area of circle - ½*7*7*sin88.8° </span>
<span>= 88.8/360*π*7² - 24.5*sin 88.8° </span>
<span>≃ 13.5 cm² </span>
<span>(using area of ∆ = ½.a.b.sin C for the triangle) </span>
<span>b) </span>
<span>volume of water = cross-sectional area * length </span>
<span>≃ 13.5 * 30 cm³ </span>
<span>≃ 404 cm³</span>
Hoped it Helped
Answer:
<h3>10</h3>
Step-by-step explanation:
If point I is on the line segment HJ, then HI+IJ = HJ
Given the parameters
H I = 2 x
H J = 4 x
IJ=4x−10
Substituting the given parameters into the formula;
2x+4x-10 = 4x
6x-10 = 4x
collect like terms
6x-4x = 10
2x = 10
divide both sides b 2;
2x/2 = 10/2
x = 5
Since IJ = 4x-10
Substitute x = 5 into IJ
IJ = 4(5)-10
IJ = 20-10
IJ = 10
