I am not sure about this but here goes nothing: d=2.5t+2.2 is very familiar to y=mx+b y=d m=2.5 x=t b=2.2 to find a new quasion we substitute d and t into place wich equals 1=2.5(0)+b simplification and you get b=1 so your answer is d=2.5t+1
<span>-Both box plots show the same interquartile range.
>Interquartile range (IQR) is computed by Q3-Q1.
For Mr. Ishimoto's class, Q3 is 35 and Q1 is 31. 35-31 = 4.
For Ms. Castillo's class, Q3 is 34 and Q1 is 30. 34-30 = 4.
</span><span>-Mr. Ishimoto had the class with the greatest number of students.
>Mr. Ishimoto had 40 students, represented by the last data point of the whiskers.
</span><span>-The smallest class size was 24 students.
>Which was Ms. Castillo's class.</span>
Answer: E. The population decreased by 11% each year.
Step-by-step explanation: In A, the pollution increases at a constant rate, but in a linear way, in other words in each day, the pollution increases 10 grams; The same goes for C: ice "grows" a few milimeters each day; In D, as volume is calculated by the multiplication of π and its radius, the increase in the volume is still linear. In B, the proportionality is related to the power of the turbine not the growth or decay of it. In E, a population grows or decreases in a form of A=A₀(1±r)^t. In this case: A = A₀ (1-0.11)^t.
In conclusion, the function that better describes an exponential growth or decay is the decrease of a population.
<span>Find
the number of columns and rows of the cupcake in a rectangle shape with 120
pieces.
=> The row must ne even and the column must be add
=> 120 = 2 x 2 x 2 x 15
=> 120 = 8 x 15
=> 120 = 120
Thus, the glee club will need to arrange the row of the rectangle shaped
cupcake as 8 rows and the column as 15
columns.
That gets the total of 120 cupcakes in all.
</span>
C. $360
$224x4=896 (total profit)
$896 (total) - $536 (first month profit) = $360 (second month profit)
