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2 years ago

In which scenario would someone want to use the Paste Link option?

1 answer:

8 0

The scenario in which someone would want to use the paste link is when Jimmy is wring an email to his friend, he copies and pastes a graph in a spreadsheet to his email to show his friend. This way the friend can follow the link to see the spreadsheet.

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Juli uses 12 ounces of cheese in her potato soup recipe. Her recipe yields 8 servings. If Juli needs enough for 20 servings, how

Ludmilka [50]

30 ounces of cheese

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1 year ago

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A certain article indicates that in a sample of 1,000 dog owners, 610 said that they take more pictures of their dog than of the

lbvjy [14]

Answer:

(a) The 90% confidence interval is: (0.60, 0.63) Correct interpretation is (3).

(b) The 95% confidence interval is: (0.42, 0.46) Correct interpretation is (1).

(c) First, the confidence level in part(b) is more than the confidence level in part(a) is, so the critical value of part(b) is more than the critical value of part(a), Second the margin of error in part(b) is more than than in part(a).

Step-by-step explanation:

(a)

Let X = number of dog owners who take more pictures of their dog than of their significant others or friends.

Given:

X = 610

n = 1000

Confidence level = 90%

The (1 - α)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The sample proportion is:

$\hat p=\frac{X}{n}=\frac{610}{1000}=0.61$

The critical value of z for a 90% confidence level is:

$z_{\alpha/2}=z_{0.10/2}=z_[0.05}=1.645$

Construct a 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends as follows:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.61\pm 1.645\sqrt{\frac{0.61(1-0.61}{1000}}\\=0.61\pm 0.015\\=(0.595, 0.625)\\\approx(0.60, 0.63)$

Thus, the 90% confidence interval for the population proportion of dog owners who take more pictures of their dog than their significant others or friends is (0.60, 0.63).

Interpretation:

There is a 90% chance that the true proportion of dog owners who take more pictures of their dog than of their significant others or friends falls within the interval (0.60, 0.63).

Correct option is (3).

(b)

Let X = number of dog owners who are more likely to complain to their dog than to a friend.

Given:

X = 440

n = 1000

Confidence level = 95%

The (1 - α)% confidence interval for population proportion is:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

The sample proportion is:

$\hat p=\frac{X}{n}=\frac{440}{1000}=0.44$

The critical value of z for a 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Construct a 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend as follows:

$CI=\hat p\pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.44\pm 1.96\sqrt{\frac{0.44(1-0.44}{1000}}\\=0.44\pm 0.016\\=(0.424, 0.456)\\\approx(0.42, 0.46)$

Thus, the 95% confidence interval for the population proportion of dog owners who are more likely to complain to their dog than to a friend is (0.42, 0.46).

Interpretation:

There is a 95% chance that the true proportion of dog owners who are more likely to complain to their dog than to a friend falls within the interval (0.42, 0.46).

Correct option is (1).

(c)

The confidence interval in part (b) is wider than the confidence interval in part (a).

The width of the interval is affected by:

The confidence level
Sample size
Standard deviation.

The confidence level in part (b) is more than that in part (a).

Because of this the critical value of z in part (b) is more than that in part (a).

Also the margin of error in part (b) is 0.016 which is more than the margin of error in part (a), 0.015.

First, the confidence level in part(b) is more than the confidence level in part(a) is, so the critical value of part(b) is more than the critical value of part(a), Second the margin of error in part(b) is more than than in part(a).

4 0

1 year ago

There are 200 students in the 7th grade class at Brookside Middle School. Of these students, 12% play volleyball and 15% play ba

Phoenix [80]

P(volleyball and baseball) = 4/200 x 100 = 2%
P(either volleyball or baseball) = P(volleyball ∪ baseball) = P(volleyball) + P(baseball) - P(volleyball and baseball) = 12% + 15% - 2% = 25%.

25% play either volleyball or baseball.

4 0

1 year ago

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Liam worked 5 hours 30minutes on Monday and 4 hours 45 minutes on Wednesday.How many total hours did Liam work on Monday and Wed

dangina [55]

5 hours + 4 hours = 9 hours
30 minutes + 45 minutes =75 minutes
60 minutes in an hour, so 75 minutes =1 hour and 15 minutes, or 1.25 hours
9 hours + 1.25 hours =10.25 hours or 10 hours and 15 minutes.

3 0

1 year ago

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The formula for the volume of a sphere is mc012-1.jpg. What is the formula solved for r? mc012-2.jpg mc012-3.jpg mc012-4.jpg mc0

NikAS [45]

Cannot see your image, but the formula for the volume of a sphere is
V=(4/3)πr³
to solve for r: r³=v÷(4/3)π=v*3/(4π)=3v/(4π) (three v out of 4 pi)
r=∛(3v/4π)
r equals the cubic root of (three v over 4π)

3 0

2 years ago

Read 2 more answers