For this case we have a function of the form:
Where,
A: initial amount
b: growth rate (if b> 1)
n: time in hours
Substituting values we have:
We have then that the initial amount is:
If b = 1.85 then the growth percentage is:
Answer:
here were initially 20 bacteria.
The hourly percent growth rate of the bacteria would be 85%
Where,
A: initial amount
b: growth rate (if b> 1)
n: time in hours
Substituting values we have:
We have then that the initial amount is:
If b = 1.85 then the growth percentage is:
Answer:
here were initially 20 bacteria.
The hourly percent growth rate of the bacteria would be 85%