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Westkost [7]
2 years ago
13

Kari bought 3 boxes of cookies to share with a book club. Each box contains 12 cookies. The expression represents the number of

cookies that each person, p, can have if the cookies are divided equally. Which evaluations of the expression are correct? Select three options.
Mathematics
2 answers:
ivanzaharov [21]2 years ago
7 0

<u>ANSWER:</u>

Kari bought 3 boxes of cookies to share. The algebraic expression is \frac{36}{x}

<u>Solution:</u>

Given, Kari bought 3 boxes of cookies to share with a book club.  

Each box contains 12 cookies.  

So, in total we have 3 x 12 cookies = 36 cookies.

Now, we have to find how many cookies can each person p will get.

Let, the total number of persons be x.

Then, after equally sharing the cookies,

\text { Number of cookies with each person }=\frac{\text {number } of \text { cookies available.}}{\text {total number of persons}}

=\frac{36}{x} \text { cookies. }

Hence, the algebraic expression is \frac{36}{x}

mrs_skeptik [129]2 years ago
6 0

Answer:

If p = 7, then each person would get 5 cookies, with 1 cookie left over.

If p = 10, then each person would get 3 cookies, with 6 cookies left over.

If p = 11, then each person would get 3 cookies, with 3 cookies left over.

B

D

E

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1 year ago
Deal with these relations on the set of real numbers: R₁ = {(a, b) ∈ R² | a &gt; b}, the "greater than" relation, R₂ = {(a, b) ∈
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Answer:

a) R1ºR1 = R1

b) R1ºR2 = R1

c) R1ºR3 = \{ (a,b) \in R^2 \}

d) R1ºR4 = \{ (a,b) \in R^2 \}

e) R1ºR5 = R1

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Step-by-step explanation:

R1ºR1

(<em>a,c</em>) is in R1ºR1 if there exists <em>b</em> such that (<em>a,b</em>) is in R1 and (<em>b,c</em>) is in R1. This means that a > b, and b > c. That can only happen if a > c. Therefore R1ºR1 = R1

R1ºR2  

This case is similar to the previous one. (<em>a,c</em>) is in R1ºR2 if there exists <em>b</em> such that (<em>a,b</em>) is in R2 and (<em>b,c</em>) is in R1. This means that a ≥ b, and b > c. That can only happen if a > c. Hence R1ºR2 = R1

R1ºR3

(a,c) is in R1ºR3 if there exists b such that a < b and b > c. Independently of which values we use for a and c, there always exist a value of b big enough so that b is bigger than both a and c, fulfilling the conditions. We conclude that any pair of real numbers are related.

R1ºR4

This is similar to the previous one. Independently of the values (a,c) we choose, there is always going to be a value b big enough such that a ≤ b and b > c. As a result any pair of real numbers are related.

R1ºR5

If a and c are related, then there exists b such that (a,b) is in R5 and (b,c) is in R1. Because of how R5 is defined, b must be equal to a. Therefore, (a,c) is in R1. This proves that R1ºR5 = R1

R1ºR6

The relation R6 is less restrictive than the relation R3, if we find 2 numbers, one smaller than the other, in particular we find 2 different numbers. If we had 2 numbers a and c, we can find a number b big enough such that a<b and b >c. In particular, b is different from a, so (a,b) is in R6 and (b,c) is in R1, which implies that (a,c) is in R1ºR6. Since we took 2 arbitrary numbers, then any pair of real numbers are related.

R2ºR3

This is similar to the case R1ºR3, only with the difference that we can take b to be equal to a as long as it is bigger than c. We conclude that any pair of real numbers are related.

R3ºR3

If a and c are real numbers such that there exist b fulfilling the relations a < b and b < c, then necessarily a < c. If a < c, then we can use any number in between as our b. Therefore R3ºR3 = R3

I hope you find this answer useful!

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