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Fiesta28 [93]
2 years ago
5

The mean of a set of credit scores is Mu = 690 and sigma = 14. Which credit score is within a z-score of 3.3? 634 640 720 750

Mathematics
2 answers:
xz_007 [3.2K]2 years ago
8 0

Answer:

720

Step-by-step explanation:

To solve this question, we would be using the formula for z- score

The formula for calculating a z-score is z = (x-μ)/σ

where x = raw score

μ = population mean

σ = sigma = population standard deviation.

From the question, we are given

The mean of a set of credit scores Mu = 690

sigma = population standard deviation 14

z - score = 3.3

This means we are to find x

z = (x-μ)/σ

3.3 = x - 690/ 14

Cross Multiply

3.3 × 14 = x - 690

46.2 = x - 690

x = 690 + 46.2

x = 736.2

Since we are told that it is a range, the closest out of the options given to our calculated x which is 736.2 is 720

Natasha2012 [34]2 years ago
7 0

Answer:

c. 720

Step-by-step explanation:

on edge

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Lera25 [3.4K]

Answer:

Sum = -81

Step-by-step explanation:

See the comment for complete question.

Given

c = 36 ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

36 ---- constant

So, the equation can be represented as:

x^2 + ax + 36 = 0

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

x = -\alpha and x = -\beta

Using the above roots, the equation can be represented as:

(x + \alpha)(x + \beta) = 0

Open brackets

x^2 + (\alpha + \beta)x + \alpha \beta = 0

To compare the above equation to x^2 + ax + 36 = 0, we have:

a = \alpha + \beta

\alpha \beta = 36

Where: \alpha, \beta and \alpha \ne \beta

The values of \alpha and \beta that satisfy \alpha \beta = 36 are:

\alpha = -1 and \beta = -36

\alpha = -2 and \beta = -18

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\alpha = -4 and \beta = -9

So, the possible values of a are:

a = \alpha + \beta

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At this point, we have established that the possible values of a are: -37, -20, -15 and -9.

The required sum is:

Sum = -37 -20 -15 - 9

Sum = -81

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