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2 years ago

The mean of a set of credit scores is Mu = 690 and sigma = 14. Which credit score is within a z-score of 3.3? 634 640 720 750

Mathematics

2 answers:

xz_007 [3.2K]2 years ago

8 0

Answer:

720

Step-by-step explanation:

To solve this question, we would be using the formula for z- score

The formula for calculating a z-score is z = (x-μ)/σ

where x = raw score

μ = population mean

σ = sigma = population standard deviation.

From the question, we are given

The mean of a set of credit scores Mu = 690

sigma = population standard deviation 14

z - score = 3.3

This means we are to find x

z = (x-μ)/σ

3.3 = x - 690/ 14

Cross Multiply

3.3 × 14 = x - 690

46.2 = x - 690

x = 690 + 46.2

x = 736.2

Since we are told that it is a range, the closest out of the options given to our calculated x which is 736.2 is 720

Natasha2012 [34]2 years ago

7 0

Answer:

c. 720

Step-by-step explanation:

on edge

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guapka [62]

Answer:

No multiplying both quantities in the ratio 60 : 36 by 1 would not give the answer .

But multiplying both quantities in the ratio 60 : 36 by 1/6 would solve it.

Step-by-step explanation:

Multiplying any number or ratio by 1 gives the same answer no matter what the expression or how much bigger the number is.This will not give the solution .

If it is multiplied with a fraction like 1/6 that would give the correct answer.

Multiplying it with 1/6 reduces the ratio and gives a better estimate.

A:B

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60*1/6: 36*1/6

10: 6

Meaning that for a total of 16 there are 10 of category A and 6 of category B.

But if we do the same procedure with the answer is same which does not solve the question.

A:B

60:36

60*1: 36*1

60: 36

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N76 [4]

Answer:65ft

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Therefore 4225=s^2

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<span>
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Read 2 more answers

Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us

grigory [225]

Answer:

The confidence interval on this case is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

$\bar X = \frac{62.532+76.478}{2}= 69.505$

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

$\bar X$ represent the sample mean