Answer:
25 posts
Step-by-step explanation:
So the number of fence post would be the total length of the log divided by the length of each post. As the log is 16m and is corrected to the nearest metre, it could possibly be 16.499m. As for the post that is 70 cm long and corrected to the nearest 10cm, it may as well be 65 cm (or 0.65m) each post
So the max number of fence point once can possibly cut from the log would be
16.499 / 0.65 = 25 posts
Answer:
I think its choice C
Step-by-step explanation:
Because it makes more sense to me
5 * 1.5 to get 7.5, which is total pounds
7.5 - 2.8 to get how many almonds
= 4.7
Choice C makes the most sense to get that answer
i'm only in 5th grade so tell me if i'm wrong ill be ok with that
Answer: He is not correct.
Steps:
Let x1 and x2 be the first and second number, respectively.
In words, if the second is 125%, or 5/4 of the first number (first equation),
then the first is 4/5 of the second, which is 0.8 or 80%.
(3/4)∗π∗62=27π
Also , the goat can reach around the corners by 2 on the short sides and 1 on long side.creating 2 90 degree sectors of additional grazing area.(1/4)∗π∗22=π
(1/4)∗π∗12=π/4
27π+π+π/4=28.25π
Answer:
There is 8% (P=0.08) that Frances concludes that the new equipment increases the average daily jewelry production when in fact the new equipment has no effect.
Step-by-step explanation:
We have one-sample z-test with a significance level of 0.08 and a power ot the test of 0.85.
In this test, the null hypothesis will state that the new equipment has the same productivity of the older equipment. The alternative hypothesis is that there is a significative improvement from the use of new equipment.
The probability that Frances concludes that the new equipment increases the average daily jewelry production when in fact the new equipment has no effect is equal to the probability of making a Type I error (rejecting a true null hypothesis).
The probability of making a Type I error is defined by the level of significance, and in this test this value is α=0.08.
Then, there is 8% that Frances concludes that the new equipment increases the average daily jewelry production when in fact the new equipment has no effect.
