Answer:
Option B. 5P5 × 20P15
Step-by-step explanation:
It is very important to remember that the second grade students are sitting in the front row, therefore, it is only necessary to organize 15 first grade students in 20 seats.
Permutations allow you to calculate the number of ways in which m objects can be arranged in n positions.
The permutation of m in n is written as:
nPm
Where n is the number of elements and m are chosen.
The way in which the 5 second grade students can be organized in the 5 seats is from the first row is:
5P5
Then, the number of ways in which 15 first-year students can be organized into 20 seats is:
20P15
Then, the number of ways to organize all students on the bus is the product of both permutations
5P5 * 20P15
First break= 1/2
second break = 1/2 of half= 1/4
third break = half of 1/4 = 1/8
forth break = 1/2 of 1/8 = 1/16
fifth break = 1/2 of 1/16 =1/32
fraction painted = 1 -1/32 =31/32
portion painted = 150*31/32 = 145.3125 ft^2
They could miss each other 30 different ways. I solved this by drawing it out six different stores and making Alice and Betsy go to each one may different times. Example photo included for how I got the first five. Then I did the same thing, but switch A and B, counted that towards the total and continued the is drawing until all the possibilities were found.
S(t) = -4.9t^2 + 19.6t + 24.5
when it reaches the ground s(t) = 0
so we have -4.9t^2 + 19.6t + 24.5 = 0
solve this for t:-
-4.9(t^2 - 4t - 5) = 0
(t + 1)(t - 5) = 0
so required time t = 5 seconds
answer 5 seconds
