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2 years ago

The output is eleven more than the input

2 answers:

8 0

X is the input and y is the output, "more" indicates addition, so 11 more than the input equals x + 11. Answer: y = x + 11

masya89 [10]2 years ago

5 0

More than means to apply addition.

11 + x

Now have the output.
<span>
y = x + 11</span>

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A normal distribution curve, where x = 70 and σ = 15, was created by a teacher using her students’ grades. What information abou

mash [69]

Answer:

The median and mode of the students grade is 70.

Most of the students scored between 40 and 100.

Step-by-step explanation:

From the provided information it can be seen that the mean of the distribution is, <em>μ</em> = 70 and the standard deviation is, <em>σ</em> = 15.

For a Normal distributed data the mean, median and mode are the same.

So, the median and mode of the students grade is 70.

The standard deviation of the data represents the spread of the observation, i.e. how dispersed the values are along the curve.

In statistics, the 68–95–99.7 rule, also recognized as the empirical rule, is a shortcut used to recall that 68.27%, 95.45% and 99.73% of the values of a Normally distributed data lie within one, two and three standard deviations of the mean, respectively.

$P(\mu-\sigma$

$P(\mu-2\sigma$

$P(\mu-3\sigma$

Assuming that maximum marks of the exam is 100, it can be said that most of the students scored between 40 and 100.

3 0

2 years ago

Read 2 more answers

Last Saturday, there were 1486 people at the Cineplex. There were about the same number of people in each of the 6 theaters. Bet

grigory [225]

<span>247 and 248 I.e. 247 in two thetheatres and 248 in the other 4. Hence 1486</span>

5 0

1 year ago

Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m

Dovator [93]

Option a: $\frac{m^{5} }{162n}$ is the equivalent expression.

Explanation:

The expression is $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ where $m\neq 0, n\neq 0$

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

$\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }$

Cancelling the like terms, we have,

$\frac{3^{-3}m^{5} n^{-1}}{6 }$

This equation can also be written as,

$\frac{m^{5}}{3^{3}6 n^{1} }$

Multiplying the terms in denominator, we have,

$\frac{m^{5} }{162n}$

Thus, the expression which is equivalent to $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ is $\frac{m^{5} }{162n}$

Hence, Option a is the correct answer.

8 0

2 years ago

Read 2 more answers

Point I is on line segment H J ‾ HJ . Given H I = 2 x , HI=2x, H J = 4 x , HJ=4x, and I J = 4 x − 10 , IJ=4x−10, determine the n

Cloud [144]

Answer:

Step-by-step explanation:

If point I is on the line segment HJ, then HI+IJ = HJ

Given the parameters

H I = 2 x

H J = 4 x

IJ=4x−10

Substituting the given parameters into the formula;

2x+4x-10 = 4x

6x-10 = 4x

collect like terms

6x-4x = 10

2x = 10

divide both sides b 2;

2x/2 = 10/2

x = 5

Since IJ = 4x-10

Substitute x = 5 into IJ

IJ = 4(5)-10

IJ = 20-10

IJ = 10

5 0

2 years ago

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Which function represents g(x), a reflection of f(x) = On a coordinate plane, 2 exponential functions are shown. g (x) decreases

Vanyuwa [196]

Answer:

$g(x)=\frac{1}{2}(3^{-x})$

Step-by-step explanation:

Given:

The graph of function $f(x)\ and\ g(x)$ are given.

The equation for $f(x)$ is given as:

$f(x)=3^x$

Now, the graph of $g(x)$ is a reflection of $f(x)$ .

The graph of $g(x)$ passes through the point (-1, 1.5) [second quadrant] and crosses the y-axis at (0, 0.5).

As evident from the graph, the functions $f(x)\ and\ g(x)$ are reflections about the y-axis.

We know the transformation rule for reflection about the y-axis as:

$f(x)\to f(-x)\\\\\therefore 3^x\to3^{-x}....(\textrm{Reflection about y-axis})$

Now, the y-intercept of the function $y=3^{-x}$ is obtained by plugging in $x=0$ . This gives,

$y=3^0=1$

So, the y-intercept is at (0, 1). But the graph of $g(x)$ crosses the y-axis at (0, 0.5). As we observe, the coordinate rule for the transformation can be written as:

(0, 1) → (0, 0.5)

$(x,y)\to (x,\frac{1}{2}y)$

So, the reflected graph is compressed vertically by a factor of $\frac{1}{2}$ .

Therefore, the transformation is given as:

$y\to \frac{1}{2}y\\\\\therefore 3^{-x}\to \frac{1}{2}(3^{-x})$

Therefore, the equation for $g(x)$ is:

$g(x)=\frac{1}{2}(3^{-x})$

8 0

1 year ago

Read 3 more answers