The table shows the gallons of water in a pool over time.
2 answers:
Answer:
- 6 gallons per minute.
Step-by-step explanation:
Let the function that models the quantities of water, Q (in gallons) in a pool over time, t (in minutes), is
Q = a + bt ........... (1)
Now, Q(t = 0) is given to be 50 gallons.
So, a = 50 and b denotes the rate at which the quantity of water in the pool is decreasing and it is given by the slope of equation (1).
Now, two points on the graph are (0,50) and (1,44).
So, the slope = b = = - 6 gallons per minute.
Therefore, the equation of this situation is given by Q = 50 - 6t, where the slope is equal to - 6 gallons per minute. (Answer)
You might be interested in
Answer:
(a1) The probability that temperature increase will be less than 20°C is 0.667.
(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.
(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.
(c) The expected value of the temperature increase is 17.5°C.
Step-by-step explanation:
Let <em>X</em> = temperature increase.
The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].
The probability density function of <em>X</em> is:
(a1)
Compute the probability that temperature increase will be less than 20°C as follows:
Thus, the probability that temperature increase will be less than 20°C is 0.667.
(a2)
Compute the probability that temperature increase will be between 20°C and 22°C as follows:
Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.
(b)
Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:
Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.
(c)
Compute the expected value of the uniform random variable <em>X</em> as follows:
Thus, the expected value of the temperature increase is 17.5°C.