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Ksivusya [100]
2 years ago
7

At Katya’s fruit stand, a basket of strawberries costs $4 and a basket of raspberries costs $9. In one morning, Katya sells 96 b

askets for $644. How many baskets of strawberries were sold?

Mathematics
1 answer:
Tcecarenko [31]2 years ago
4 0

Answer:

The number of strawberry baskets sold was 44

Step-by-step explanation:

Let

x ----> the number of strawberry baskets sold

y ---> the number of raspberries baskets sold

we know that

In one morning, Katya sells 96 baskets for $644

so

x+y=96 ----> equation A

4x+9y=644 ---> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (44.52)

see the attached figure

therefore

The number of strawberry baskets sold was 44 and the number of raspberries baskets sold was 52

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Marlene rides her bike at a rate of 16 miles per hour. The time in hours that she rides is represented by the variable t, and th
White raven [17]

Let

t--------> the time in hours

d-------> the distance in miles

we know that

d=16t

this is a linear equation that represent the scenario

in this equation the independent variable is the time t and the dependent variable is the distance d

The distance's equation in function notation is equal to

f(t)=16t

Using a graph tool

see the attached figure

The domain of the function is the interval----------> [0,∞)

t\geq0

The range of the function is the interval------->  [0,∞)

f(t)\geq0

<u>Statements</u>

<u>a) The independent variable, the input, is the variable d, representing distance</u>

The statement is false

Because the  independent variable is the variable t

<u>b) The distance traveled depends on the amount of time Marlene rides her bike</u>

The statement is true

Because the distance's equation in function notation is equal to

f(t)=16t

<u>c) The initial value of the scenario is 16 miles per hour</u>

The statement is false

Because 16 represent the rate or  the slope of the linear equation

<u>d) The equation t = d + 16 represents the scenario</u>

The statement is false

Because, the scenario is represented by the function f(t)=16t

<u>e) The function f(t) = 16t represents the scenario</u>

The statement is true

8 0
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It will be a kid getting hit in the leg by the kids in the lunch table so it will be 4
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The most popular mathematician in the world is throwing aparty for all of his friends. As a way to kick things off, they decidet
ratelena [41]

Answer:

The no. of possible handshakes takes place are 45.

Step-by-step explanation:

Given : There are 10 people in the party .

To Find: Assuming all 10 people at the party each shake hands with every other person (but not themselves, obviously) exactly once, how many handshakes take place?

Solution:

We are given that there are 10 people in the party

No. of people involved in one handshake = 2

To find the no. of possible handshakes between 10 people we will use combination over here

Formula : ^nC_r=\frac{n!}{r!(n-r)!}

n = 10

r= 2

Substitute the values in the formula

^{10}C_{2}=\frac{10!}{2!(10-2)!}

^{10}C_{2}=\frac{10!}{2!(8)!}

^{10}C_{2}=\frac{10 \times 9 \times 8!}{2!(8)!}

^{10}C_{2}=\frac{10 \times 9 }{2 \times 1}

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Find a122 of the sequence 5, 8, 11
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5, 8, 11, ... is an arithmetic sequence where:

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8 0
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Which of the following functions is graphed below?
dalvyx [7]

Answer:

The function graphed is y = Ix - 5I - 4 ⇒ answer D

Step-by-step explanation:

* Lets explain how to solve this problem

- From the graph

# The graph intersects the x-axis at x = 1 and x = 9

∴ The x-intercepts are 1 and 9

- We can find x-intercept by equate y by 0

* Lets equate the answers by zero to find the x-intercept

# y = Ix + 5I - 4

∵ Ix + 5I - 4 = 0

- Add 4 to both sides

∴ Ix + 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix + 5I = 4

∴ x + 5 = 4 ⇒ subtract 5 from both sides

∴ x = -1

- OR

∴ x + 5 = -4 ⇒ subtract 5 from both sides

∴ x = -9

∴ The x-intercepts are -1 and -9 not the same with figure

# y = Ix - 5I + 4

∵ Ix - 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix - 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

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∴ We can't solve this equation

# y = Ix + 5I + 4

∵ Ix + 5I + 4 = 0

- Subtract 4 from both sides

∴ Ix + 5I = -4

- Remember in Ia + bI = c , c can't be negative because the absolute

 value is always positive

∴ We can't solve this equation

# y = Ix - 5I - 4

∵ Ix - 5I - 4 = 0

- Add 4 to both sides

∴ Ix - 5I = 4

- Remember in Ia + bI = c, then we have two answers :

 a + b = c  <em>OR </em> a + b = -c

∵ Ix - 5I = 4

∴ x - 5 = 4 ⇒ add 5 to both sides

∴ x = 9

- OR

∴ x - 5 = -4 ⇒ add 5 to both sides

∴ x = 1

∴ The x-intercepts are 1 and 9 the same with figure

* The function graphed is y = Ix - 5I - 4

5 0
2 years ago
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