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2 years ago

Find the constant of variation k for the direct variation 2x +6y = 0

1 answer:

5 0

A relationship between two variables in which one is a constant multiple of the other. The constant here is also called the constant of variation. In order to obtain this value, we manipulate the equation by isolating the variables. We do as follows:

2x +6y = 0
y = -x/3

Therefore, the constant of variation is -1/3. Hope this answers the question. Have a nice day.

You might be interested in

. Simplify (−34.67)0

maksim [4K]

If it's -34*0 then it is equal to 0 because anything times 0 is 0.

If it were -34.67 to the power of 0, then It would have been equal to -1. This is because anything to the power of 0 is 1. In this case though the base is negative so it would be -1.

But the answer is 0.

5 0

2 years ago

A circular logo is enlarged to fit the lid of a jar. The new diameter is 50 per cent larger than the original. By what percentag

laila [671]

25% because u have to divide the diameter of the logo to get the radius.

4 0

2 years ago

Which quadratic equation is equivalent to (x – 4)2 – (x – 4) – 6 = 0?

Viktor [21]

I hope choices must be given in the problem.

I am showing the method to find the equivalent equation of the above equation. You can match with your given choices.

First step is to expand the first term. So,

(x-4)² = (x - 4)(x - 4) Since a²= a*a

= x² - 4x - 4x + 4 * 4 By multiplying.

= x² -8x + 16 Combine the like terms.

So, (x - 4)² - (x -4) - 6

= x² - 8x + 16 - x + 4 - 6

= x² - 9x + 14 Combine the like terms.

So, equivalent equation of the above equation is x² - 9x + 14 = 0.

5 0

2 years ago

Read 2 more answers

Water is poured into a conical paper cup at the rate of 3/2 in3/sec (similar to Example 4 in Section 3.7). If the cup is 6 inche

aliya0001 [1]

Answer:

The water level rising when the water is 4 inches deep is $\frac{3}{8\times \pi} inch/s$ .

Step-by-step explanation:

Rate of water pouring out in the cone = R= $\frac{3}{2} inch^3/s$

Height of the cup = h = 6 inches

Radius of the cup = r = 3 inches

$\frac{r}{h}=\frac{3 inch}{6 inch}=\frac{1}{2}$

r = h/2

Volume of the cone = $V=\frac{1}{3}\pi r^2h$

$V=\frac{1}{3}\pi r^2h$

$\frac{dV}{dt}=\frac{d(\frac{1}{3}\pi r^2h)}{dt}$

$\frac{dV}{dt}=\frac{d(\frac{1}{3}\pi (\frac{h}{2})^2h)}{dt}$

$\frac{dV}{dt}=\frac{1}{3\times 4}\pi \times \frac{d(h^3)}{dt}$

$\frac{dV}{dt}=\frac{1\pi }{12}\times 3h^2\times \frac{dh}{dt}$

$\frac{3}{2} inch^3/s=\frac{1\pi }{12}\times 3h^2\times \frac{dh}{dt}$

h = 4 inches

$\frac{3}{2} inch^3/s=\frac{1\pi }{12}\times 3\times (4inches )^2\times \frac{dh}{dt}$

$\frac{3}{2} inch^3/s=\pi\times 4\times \frac{dh}{dt} inches^2$

$\frac{dh}{dt}=\frac{3}{8\times \pi} inch/s$

The water level rising when the water is 4 inches deep is $\frac{3}{8\times \pi} inch/s$ .

6 0

2 years ago

You are checking the intermediate results of a phone app that calculates the weight of an object in kilograms given the weight i

Illusion [34]

The wrong step is step 4, because you only need one conversion.

The formula to convers pounds to kilograms is

$\text{weight in pounds} = 2.2 \times \text{weight in kilograms}$

Obviously, the inverse formula is

$\text{weight in kilograms} = \cfrac{\text{weight in pounds}}{2.2}$

So, you're given an input of 142 pounds. To convert it in kilograms, plug that value into out formula:

$\text{weight in kilograms} = \cfrac{142}{2.2} \approx 64.5$

and this is the answer you're looking for, so you need no more steps.

4 0

2 years ago