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2 years ago

In triangle ABC AD/DB = CE/EB. Complete the proof showing the segment DE is parallel to segment AC.

Mathematics

1 answer:

Natasha_Volkova [10]2 years ago

5 0

Answer:

1. $\dfrac{AD}{DB}+1=\dfrac{CE}{EB}+1$

2. Addition property of equality

Step-by-step explanation:

In triangle ABC,

$\dfrac{AD}{DB}=\dfrac{CE}{EB}.$

The addition property of equality states that if the same amount is added to both sides of an equation, then the equality is still true.

Use addition property of equality, add 1 to both sides of previouse equality:

$\dfrac{AD}{DB}=\dfrac{CE}{EB}\\ \\\dfrac{AD}{DB}+1=\dfrac{CE}{EB}+1\\ \\\dfrac{AD+DB}{DB}=\dfrac{CE+EB}{EB}$

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I added a screenshot of the complete question.

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