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Alenkinab [10]
2 years ago
7

Help 20 points ,

Mathematics
2 answers:
eimsori [14]2 years ago
6 0

I think your answer would be C, if I am correct.


:p


sweet-ann [11.9K]2 years ago
4 0
The answer would be D
You might be interested in
Please, I'm confuse!
Ivahew [28]

OK.  You asked for it.  Here we go.
First, let's gather up the tools we might use ...
some things that we know about triangles:

-- Every triangle:  Area = (1/2) x (length of the base) x (the height)

-- Isosceles triangle:  It has two sides that are the same length.

-- Right triangle:  It has one right angle in it. 
The sides that meet at the right angle are called the "legs". 
They form a corner there, like this      _|     .
-------------------------------------------
Now we can start using these tools to hack away at the problem.
Farmer Ted has an isosceles right triangle garden.
The problem asks us to figure out how long the legs are.

Before he changes anything, it looks like this   _|   and both of
those sides are the same length.  Call it  'x' until we figure out
what it really is.

Notice that one of them is the base of the triangle, and the other one
is the height.  So the area of this triangle is

                           (1/2) (x) (x)  or  (1/2) x² .

-------------------------------

Farmer Ted is never satisfied.  Suddenly, one day without warning, he
comes along and makes the garden bigger.  He makes one of the legs 
7  ft longer, and he makes the other one  5 ft longer.

Now the length of one leg is  (x + 7)  and the other one is (x + 5) .
They're still the base and height of the triangle, so the area of the
bigger garden is
                           (1/2) (x + 7) (x + 5).

The problem says that this area is 55 square feet more than the original
area, so look out, here comes the <em>equation </em>:

                       new area         =      old area +  bigger

                (1/2) (x + 7) (x + 5)  =      (1/2) x²  +  55

Locked in the mysterious shadowy crevices of this equation is
everything we need in order to figure out the original length of the legs ...
what we called  'x'.

At this point, we can forget about Farmer Ted, forget about the garden,
and just go back to our laboratory with this equation and solve it to find  'x'.

Let's take it slow and easy, one little step at a time:

                                     <u>(1/2) (x + 7) (x + 5)  =  (1/2) x² + 55</u>

Multiply each side by 2 :         (x + 7) (x + 5)  =         x² +  110

Expand (FOIL) the left side:     x² + 12x + 35  =         x² + 110

Subtract  x²  from each side:          12x + 35  =                 110

Subtract  35  from each side:          12x         =                  75

Divide each side by  12 :                           <em>x  =  6.25 feet</em>

==============================================

OK.  That's a very nice number.  How do we know whether it's correct ?
Let's check it out, and see if it fits the story:

Original area = (1/2 x base x height) = (0.5 x 6.25 x 6.25) = 19.53125 sq ft

One new leg = (6.25 + 7) =   13.25 ft
Other new leg = (6.25 + 5) = 11.25 ft

New area = (1/2 x base x height) = (0.5 x 13.25 x 11.25) = 74.53125 sq ft

How much bigger is the new area ?

         74.53125 - 19.53125  =  <em>55 sq ft  </em>    yay !

When we start with legs that are  6.25-ft  and go through the whole story,
the new area is exactly what the problem says it was.  So  6.25-ft  is the
correct original length of the legs, before Farmer Ted messed with it.


7 0
2 years ago
Q: Angelica uses the point (4,3) to represent the location of her house and uses the point (10,8) to represent the location of a
oksian1 [2.3K]

Answer:

The answer to your question is 7.8 mi

Step-by-step explanation:

Data

H (4,3)

G (10, 8)

Process

1.- Use the distance between to points formula to find the distance

        dHG = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}

x1 = 4       y1 = 3

x2 = 10    y2 = 8

2.- Substitution

         dHG = \sqrt{(10 - 4)^{2} + (8 - 3)^{2}}

3.- Simplification

         dHG = \sqrt{6^{2} + 5^{2}}

         dHG = \sqrt{36 + 25}

         dHG = \sqrt{61}

4.- Result

         dHG = 7.8 mi

4 0
2 years ago
Read 2 more answers
Two hundred randomly selected people were asked to state their primary source for news about current events: (1) Television, (2)
NeTakaya

Answer:

Step-by-step explanation:

Hello!

You have a sample of 200 people, they were asked their primary source of news, categorized in (1) Television, (2) Radio, (3) Internet and (4) Other.

And your objective is to test if the proportions in this sample follow the known frequencies 10%, 30%, 50%, and 10%.

The propper statistic test to use to probe if the sample follows the known or historical distribution is Chi-Square goodness of fit test. In this test, what you state in the null hypothesis is the model or distribution you want to test. In this case, you've to write down the proportions for each category:

H₀: P(1)= 0.10; P(2)= 0.30; P(3)= 0.50; P(4)= 0.10

I hope you have a SUPER day!

7 0
2 years ago
Suppose c and d vary inversely, and d = 2 when c = 17.
balu736 [363]

Answer:

c = 34/d

d = 1/2

Step-by-step explanation:

Part A

Basic Formula

c = k/d

17 = k/2         Multiply both sides by 2

17*2 = k*2/2     Combine

34 = k

So the equation is c = 34/d

Part B

c = 68

k = 34

d = ?

68 = 34/d               Multiply both sides by d

68*d = 34 * d/d      Simplify.

68 d = 34                Divide by 68

d = 34/68                Simplify

d = 1/2

5 0
2 years ago
Discuss the validity of the following statement. If the statement is always​ true, explain why. If​ not, give a counterexample.
Zarrin [17]

Correction:

Because F is not present in the statement, instead of working on​P(E)P(F) = P(E∩F), I worked on

P(E∩E') = P(E)P(E').

Answer:

The case is not always true.

Step-by-step explanation:

Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.

And for any two mutually exclusive events, E and E',

P(E∩E') = 0

Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then

P(E)P(E') cannot be equal to zero.

So

P(E)P(E') ≠ 0

This makes P(E∩E') different from P(E)P(E')

Therefore,

P(E∩E') ≠ P(E)P(E') in this case.

8 0
2 years ago
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