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2 years ago

The radius of a cylinder is 5" and the lateral area is 70 sq. in. Find the length of the altitude. 2.8" 7" 14"

1 answer:

algol132 years ago

5 0

The correct question is
<span>The radius of a cylinder is 5" and the lateral area is 70pi sq. in. Find the length of the altitude.
</span>
we know that

[surface lateral area]=(2*pi*r)*height
height= [surface lateral area]/(2*pi*r)
surface lateral area=70*pi in²
r=5 in
so
height= [70*pi]/(2*pi*5)------> 7 in

the answer is
7 in

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No these these result do not differ at 95% confidence level

Step-by-step explanation:

From the question we are told that

The first concentrations is $c _1= 30.0 \ g/m^3$

The second concentrations is $c _2 = 52.9 \ g/m^3$

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The second sample size is $n_2 = 32$

The first standard deviation is $\sigma_1 = 30.0$

The first standard deviation is $\sigma_1 = 29.0$

The mean for Turnpike is $\= x _1 = \frac{c_1}{n} = \frac{31.4}{32} = 0.98125$

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The null hypothesis is $H_o : \mu _1 - \mu_2 = 0$

The alternative hypothesis is $H_a : \mu _1 - \mu_2 \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }}$

$t = \frac{0.98125 - 1.6531}{ \sqrt{\frac{30^2}{32} +\frac{29^2}{32} }}$

$t = - 0.0899$

Generally the degree of freedom is mathematically represented as

$df = 32+ 32 - 2$

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$\alpha = (C - 100 )\%$

=> $\alpha = (95 - 100 )\%$

=> $\alpha =0.05$

The critical value is evaluated as

$t_c = 2 * t_{0.05 , 62}$

From the student t- distribution table

$t_{0.05, 62} = 1.67$

$t_c = 2 * 1.67$

=> $t_c = 3.34$

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$t_c > t$ we fail to reject the null hypothesis so this mean that the result do not differ

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