You need to look at this chart <span>The system of equations below represents the number of people and total sales for the county fair on Tuesday, where x represents the number of child tickets and y represents the number of adult tickets. you need to take the amount of money you get for adult tickets only then divid it by seven and that is you answer</span>
Answer: 21 square units
Step-by-step explanation:
We know that the area of parallelogram is given by:-
Let US denote the height of the Parallelogram RSTU with corresponding base ST.
By counting the distance between the points using grids or by distance formula,
US=
ST=
Now, the area of parallelogram RSTU is given by:-
Answer:
12
Step-by-step explanation:
0.8 is equal to 80%
you need to figure out 80% of 15
100% = 15
10% = 1.5
(x8)
80% = 12
you would need to shade 12 out of 15 boxes which gives 0.8 chance of picking a shaded one
Answer:
a)0.099834
b) 0
Step-by-step explanation:
To solve for this question we would be using , z.score formula.
The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
A candy maker produces mints that have a label weight of 20.4 grams. Assume that the distribution of the weights of these mints is normal with mean 21.37 and variance 0.16.
a) Find the probability that the weight of a single mint selected at random from the production line is less than 20.857 grams.
Standard Deviation = √variance
= √0.16 = 0.4
Standard deviation = 0.4
Mean = 21.37
x = 20.857
z = (x-μ)/σ
z = 20.857 - 21.37/0.4
z = -1.2825
P-value from Z-Table:
P(x<20.857) = 0.099834
b) During a shift, a sample of 100 mints is selected at random and weighed. Approximate the probability that in the selected sample there are at most 5 mints that weigh less than 20.857 grams.
z score formula used = (x-μ)/σ/√n
x = 20.857
Standard deviation = 0.4
Mean = 21.37
n = 100
z = 20.857 - 21.37/0.4/√100
= 20.857 - 21.37/ 0.4/10
= 20.857 - 21.37/ 0.04
= -12.825
P-value from Z-Table:
P(x<20.857) = 0
c) Find the approximate probability that the sample mean of the 100 mints selected is greater than 21.31 and less than 21.39.
