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yaroslaw [1]
2 years ago
7

A tank has 908.64 litres of water . It has to be poured into buckets of capacity 50.48 , find the number of buckets required

Mathematics
2 answers:
omeli [17]2 years ago
7 0

18 buckets would be the answer.


Usimov [2.4K]2 years ago
4 0
The answer is 18. You have to divide 908.64 by 50.48 to get the answer of 18.
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Step-by-step explanation:

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On Tuesday, 525 people bought tickets to the county fair. Tickets cost $7 for adults and $3 for children. The total revenue from
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What is the area of parallelogram RSTU? 21 square units 24 square units 28 square units 32 square units
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Answer: 21 square units

Step-by-step explanation:

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A=height\times base

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7 0
2 years ago
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Given a grid with 15 sections, determine how many sections in the grid need to be shaded so the probability of a point chosen at
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12

Step-by-step explanation:

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a)0.099834

b) 0

Step-by-step explanation:

To solve for this question we would be using , z.score formula.

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

A candy maker produces mints that have a label weight of 20.4 grams. Assume that the distribution of the weights of these mints is normal with mean 21.37 and variance 0.16.

a) Find the probability that the weight of a single mint selected at random from the production line is less than 20.857 grams.

Standard Deviation = √variance

= √0.16 = 0.4

Standard deviation = 0.4

Mean = 21.37

x = 20.857

z = (x-μ)/σ

z = 20.857 - 21.37/0.4

z = -1.2825

P-value from Z-Table:

P(x<20.857) = 0.099834

b) During a shift, a sample of 100 mints is selected at random and weighed. Approximate the probability that in the selected sample there are at most 5 mints that weigh less than 20.857 grams.

z score formula used = (x-μ)/σ/√n

x = 20.857

Standard deviation = 0.4

Mean = 21.37

n = 100

z = 20.857 - 21.37/0.4/√100

= 20.857 - 21.37/ 0.4/10

= 20.857 - 21.37/ 0.04

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P-value from Z-Table:

P(x<20.857) = 0

c) Find the approximate probability that the sample mean of the 100 mints selected is greater than 21.31 and less than 21.39.

5 0
2 years ago
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