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Evgen [1.6K]
2 years ago
13

June needs 48 gallons of punch

Mathematics
2 answers:
LenaWriter [7]2 years ago
8 0

Answer:

David needs 36.style="color:rgb(72,72,72);background-color:transparent;"> gallons of punch for a party and has two different coolers to carry it in. The bigger cooler is 5. times as large as the smaller cooler.

nikdorinn [45]2 years ago
5 0

Answer:

Smaller cooler can hold 8 gallons and the bigger cooler can hold 40 gallons.

Step-by-step explanation:

Given:  June needs 48 gallons of punch  for a party and has two different

coolers to carry it in. The bigger  cooler is five times as large as the

smaller cooler.

To find: How many gallons  can each cooler hold?

Solution: Let the smaller cooler can carry x gallons of punch.

As per the question, the larger cooler will carry 5x gallons of punch.

Now, it is given that June needs 48 gallons of punch for a party.

So, we have an equation as x+5x=48

On solving, the above equation for x we have,

x+5x=48

6x=48

x=8

So, the smaller cooler can hold 8 gallons of punch and the bigger cooler can hold 8\times5=40 gallons.

Hence, smaller cooler can hold 8 gallons of punch and the bigger cooler can hold 40 gallons of punch.

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The Office of Student Services at UNC would like to estimate the proportion of UNC's 34,000 students who are foreign students. I
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Answer:

Mean is 3.05

Standard deviation is 1.69.

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2 years ago
For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

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Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

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12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

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Step 3. Replace equation (2) in equation (5) and solve for l

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