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Otrada [13]
2 years ago
10

Strawberries cost $2 per pound. Kate buys 5 pounds and gets 20% discount on the total cost. How much does Kate pay for the straw

berries?
Mathematics
1 answer:
I am Lyosha [343]2 years ago
8 0

Answer:

8$

Step-by-step explanation:

If  strawberries cost $2 per pound and she buys 5 pounds we have to multiply the cost of 1 pound by 5.

2.5= 10

The discount of 20% is applied to the $ 10, we calculate how much the value of 20% (<em>using a simple rule of three</em>) is and subtract it from $ 10.

100\longrightarrow 10\\ 20\longrightarrow x\\ x=\frac{20.(10)}{100}= 2

(10-2)=8

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Polygon ABCD goes through a sequence of rigid transformations to form polygon A′B′C′D′. The sequence of transformations involved
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Refer to the diagram below

The shape ABCD first is reflected on the mirror line y = x

Then it is reflected again on the y-axis [equation of the line is x = 0]

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2 years ago
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Find the length of DF or state what additional information you would need to find it.
hichkok12 [17]

Answer:

DF=3.75

Step-by-step explanation:

24/6=15/x

cross multiply to get 24x=90

x=3.75

5 0
2 years ago
The rate of transmission in a telegraph cable is observed to be proportional to x2ln(1/x) where x is the ratio of the radius of
sergij07 [2.7K]

Answer:

The value of x that gives the maximum transmission is 1/√e ≅0.607

Step-by-step explanation:

Lets call f the rate function f. Note that f(x) = k * x^2ln(1/x), where k is a positive constant (this is because f is proportional to the other expression). In order to compute the maximum of f in (0,1), we derivate f, using the product rule.

f'(x) = k*((x^2)'*ln(1/x) + x^2*(ln(1/x)')) = k*(2x\,ln(1/x)+x^2*(\frac{1}{1/x}*(-\frac{1}{x^2})))\\= k * (2x \, ln(1/x)-x)

We need to equalize f' to 0

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  • 2x ln(1/x) - x = 0 -------- Now we take the x and move it to the other side
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  • ln(1/x) = x/2x = 1/2 -------  we send the natural logarithm as exp
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7 0
2 years ago
Production of passenger cars in Japan increased from 3.94 million in 1999 to 6.74 million in 2009. What is the geometric mean an
vovangra [49]

Let's assume initial population is in 1999

so, production of passenger cars in Japan is 3.94 million in 1999

so, P=3.94 million

and the  production of passenger cars in Japan is 6.74 million in 2009

so, A=6.74 million in t=2009-1999=10 years

now, we can use formula

A=P(1+r)^t

here , r is interest rate

so, we can plug values

6.74=3.94(1+r)^{10}

now, we can solve for

\left(1+r\right)^{10}=\frac{337}{197}

r=0.05516

so,

the geometric mean annual percent increase is 5.516%............Answer

7 0
2 years ago
Lee needed to make drapes the length from the floor to the top of the window. The wall beneath the window had the height of 2 2/
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We\ should\ sum \ those \ two\ measurements\ to \ obtain\ length\ of\ drapes\\\\&#10;2 \frac{2}{3}+2\frac{3}{4}=\frac{8}{3}+\frac{11}{4}=\frac{24}{12}+\frac{33}{12}=\frac{57}{12} =4,75feet
3 0
2 years ago
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