<h3>
(a)Probability of cancelling at least 4 classes is 0.0055.</h3><h3>
(b)Probability of 10th class is third class that gets cancelled
= 0.0031</h3>
Step-by-step explanation:
Here, the question is<u> incomplete</u>.
Every day, a lecture may be canceled due to inclement weather with probability 0.05. Class cancellations on different days are independent.
(a) There are 15 classes left this semester. Compute the probability that at least 4 of them get canceled.
(b) Compute the probability that the tenth class this semester is the third class that gets canceled.
Now, here:
The probability of cancelling each class = 0.05
Now, probability of cancelling at least 4 classes
= 1 - P(Cancelling at max 3 classes)
= 1 - P(0 ≤ x ≤ 3) = 1 - Binomial (15,0.05,3)
= 0.0055
Hence, probability of cancelling at least 4 classes is 0.0055.
(b) As given, 10th class is third class that gets cancelled.
So, the first and second classes that get cancelled in between 1 - 9.
P(2 class cancelled in 1st 9) = Binomial (15,0.05,3) = 0.0629
Also, as given P(10th class cancelled) = 0.05
⇒ P(10th class is third class that gets cancelled ) = 0.0629 x 0.05 = 0.0031
