Data on the oxide thickness of semiconductor wafers are as follows: 425, 431, 416, 419, 421, 436, 418, 410, 431, 433, 423, 426,
DanielleElmas [232]
Answer:
423
Step-by-step explanation:
The sample mean is a point estimate of the population mean.
Therefore a point estimate of the mean oxide thickness for all wafers in the population is the mean of the sample data on the oxide thickness of semiconductor wafers.
To calculate the sample mean, we sum all the sample data and divide by the sample size which is 24. We get 423.33 ≈423
Answer: I think its D. 1:5
Step-by-step explanation:
but im not surr
Answer:
<u>The correct answer is A. 16.5%</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly and to calculate the trend:
2006 2007 Trend
Top Coats 297 223 -24.92%
Parkas 210 210 + 0%
Jackets 213 285 +33.80%
Raincoats 137 259 +89.05
Trench coats 103 127 +23.30%
Total 960 1,104 +15%
2. If the trend shown in these graphs stays constant, what percent of the market will parkas occupy in 2008?
Let's calculate the percent of the market occupied by parkas.
In 2006 = 210/960 = 21.88%
In 2007 = 210/1,104 = 19.02%
In 2008 = 210/1,270 = 16.54% (210 + 0 = 210; 1,104 + 15% = 1,270)
<u>The correct answer is A. 16.5%</u>
Answer:
For this case assuming that the random variable is X

And replacing n = 24 we got:

And we notate the distribution we got: 
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
For this case assuming that the random variable is X

And replacing n = 24 we got:

And we notate the distribution we got: 
Calculation:
<span>3/10 </span><span><span> 3---------></span>3% discount</span><span><span>
10--------></span>the days in the discount period, the company has 10 days to pay the bill in full.</span>
Therefore
Lyman pays the
balance within the discount period
($4,200 – $750) x .03 = $103.50
the
discount is <span>$103.50</span>