X<br><img src="https://tex.z-dn.net/?f=x%200.8265%20%3D%2045%20" id="TexFormula1" title="x 0.8265 = 45 " alt="x 0.8265 = 45 " al

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B12%20%7Bx%7D%5E%7B6%7D%20%20%7By%7D%5E%7B7%7D%20%7D%20%20%5Ctimes%20%20%5C

galina1969 [7]

So, we would need to remember, the one way that me personally would view square rooting would be by simplifying them, and that number would go into that number that many times. So, when doing this kind of problem, we are not truly going to do this, but we are just going to simplify it, and to see what other square "rooter" would go into that.

So, we would need to remember a (key) point, <em>we aren't just multiplying, for the most part, we're simplifying. </em>

Our result:

$\boxed{\boxed{\bf{2a^2b \sqrt[4]{24a^2b^3} }}}$

We didn't just multiplied it, we also simplified it also.

4 0

1 year ago

Tomorrow, Mrs. Wendel's class will be using toothpicks for a science project. Each student must use at least 9 toothpicks for th

Sergeeva-Olga [200]

Number of toothpicks required per student = At least 9

Total number of students = 30

Number of toothpicks required for the entire class = At least 9 × 30 = At least 270

Number of toothpicks in the bag in the class storage room = 50

Additional number of toothpicks required to be bought to make sure there are enough toothpicks = 270 - 50 = 220

Hence, she needs to buy 220 toothpicks.

4 0

2 years ago

Read 2 more answers

A plane intersects the center of a sphere with a volume of about 113.1 m3. What is the area of the cross section? Round to the n

ivolga24 [154]

Answer:

Step-by-step explanation:

$if ~radius=r \\volume =\frac{4}{3} \pi r^3\\113.1=\frac{4}{3} \pi r^3\\113.1 \times \frac{3}{4 \pi } =r^3\\\frac{339.3 }{4 \times 3.14} =r^3\\r^3=\frac{339.3}{12.56} \approx 27\\r=3\\area =\pi r^2=\pi *3^2=9\pi =9*3.14=28.26 \approx 28.3 ~m^2$

5 0

2 years ago

According to a study in a medical journal, 202 of a sample of 5,990 middle-aged men had developed diabetes. It also found that m

tekilochka [14]

Answer:

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has diabetes.

Event B: Is very active.

Probability of having diabetes:

To find this probability, we take in consideration that:

It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.

So the probability of developing diabetes is:

x of 4/5 = x of 0.8(not active)

x/4 = 0.25x of 1/5 = 0.2(very active). So

$P(A) = 0.8x + 0.25*0.2x = 0.85x$