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kirza4 [7]
1 year ago
14

On a coordinate plane, a line is drawn from point A to point B. Point A is at (negative 8, negative 13) and point B is at (4, 11

). What are the x- and y- coordinates of point P on the directed line segment from A to B such that P is One-third the length of the line segment from A to B? x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1 y = (StartFraction m Over m + n EndFraction) (y 2 minus y 1) + y 1 (1, 5) (0, 3) (–4, –5) (–5, –7)
Mathematics
2 answers:
juin [17]1 year ago
9 0
10226321 because of the minus of the (1,5) 102374711
lozanna [386]1 year ago
6 0

Answer:

c

Step-by-step explanation:

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Gary used landscape timbers to create a border around a garden shaped like a right triangle. The longest two timbers he used are
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Answer:

9 feet

Step-by-step explanation:

Given:

The border of the garden is a right angled triangle.

Two lengths are given as 12 ft and 15 ft.

Let the length of the shortest timber be 'x' feet.

Now, in a right angled triangle, the longest length is called the hypotenuse.

As 15 feet is the largest length, it is the hypotenuse of the triangle. Now, applying Pythagoras theorem, we get:

(Leg1)^2+(Leg2)^2=(Hypotenuse)^2\\x^2+12^2=15^2\\x^2+144=225\\x^2=225-144\\x^2=81\\x=\pm \sqrt{81}=\pm 9

The negative value is neglected as length can never be negative.

Therefore, the length of the shortest timber is 9 feet.

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Stacey owns a lot that has 180 feet of front footage and contains 36,000 square feet. She purchases two lots adjacent to each si
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The graph of the function f(x)=(x+2)(x+6) is shown

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Alayna worked 44 hours last week. Her hourly rate is $9.00. Alayna's gross pay for last week was $
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44 x 9 = $396.00

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A survey found that 73% of adults have a landline at their residence (event A); 83% have a cell phone (event B). It is known tha
4vir4ik [10]

Answer:

3. What is the probability that an adult selected at random has both a landline and a cell phone?

A. 0.58

4. Given an adult has a cell phone, what is the probability he does not have a landline?

C. 0.3012

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that an adult has a landline at his residence.

B is the probability that an adult has a cell phone.

C is the probability that a mean is neither of those.

We have that:

A = a + (A \cap B)

In which a is the probability that an adult has a landline but not a cell phone and A \cap B is the probability that an adult has both of these things.

By the same logic, we have that:

B = b + (A \cap B)

The sum of all the subsets is 1:

a + b + (A \cap B) + C = 1

2% of adults have neither a cell phone nor a landline.

This means that C = 0.02.

73% of adults have a landline at their residence (event A); 83% have a cell phone (event B)

So A = 0.73, B = 0.83.

What is the probability that an adult selected at random has both a landline and a cell phone?

This is A \cap B.

We have that A = 0.73. So

A = a + (A \cap B)

a = 0.73 - (A \cap B)

By the same logic, we have that:

b = 0.83 - (A \cap B).

So

a + b + (A \cap B) + C = 1

0.73 - (A \cap B) + 0.83 - (A \cap B) + (A \cap B) + 0.02 = 1

(A \cap B) = 0.75 + 0.83 - 1 = 0.58

So the answer for question 3 is A.

4. Given an adult has a cell phone, what is the probability he does not have a landline?

83% of the adults have a cellphone.

We have that

b = B - (A \cap B) = 0.83 - 0.58 = 0.25

25% of those do not have a landline.

So P = \frac{0.25}{0.83} = 0.3012

The answer for question 4 is C.

4 0
1 year ago
Write two expressions where the solution is 41
Bogdan [553]
Two consecutive numbers can be defined as x and y, but a better choice is x and x+1. . The product of the two numbers is: x(x+1). We are told this 41 more than the sum. The sum of the two numbers is: x + (x+1). . So the equation we need to solve is: . x(x+1) = x+(x+1)+41 . x^2 +x = 2x + 42 . subtract 2x from both sides . x^2 +x -2x = 2x-2x + 42 x^2 -x = 42 . subtract 42 from both sides . x^2 -x -42 = 42-42 = 0
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2 years ago
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