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PilotLPTM [1.2K]
2 years ago
5

What happens to the pressure as the volume approaches 0? Explain your reasoning

Mathematics
2 answers:
stiv31 [10]2 years ago
8 0

The pressure approaches infinity.

The function is undefined for V = 0.

There is an asymptote at V = 0.

Bumek [7]2 years ago
5 0

Answer:   The pressure 'p' will not be defined at volume 'V'=0.

Explanation:-

The given equation :-  where p is a rational function dependent on V.

A rational function is not defined for denominator = 0.

In the given function V is the denominator , if V=0 then the function will not defined.

⇒p will not be defined at V=0.

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kirill115 [55]

Answer:

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Step-by-step explanation:

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Put x=rcosA annd y=rsinA

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we know that cos^2A+sin^2A=1, so we have that

f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)

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2 years ago
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