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il63 [147K]
2 years ago
11

The table shows data from a survey about the number of times families eat at restaurants during a week. The families are either

from Rome, Italy or New York, New York:
           High   Low   Q1     Q3    IQR   Median    Mean        σ
Rome 18         1        3       7       4         6.5       6.4           4.3
NY      14        1       4.5    8.5      4        5.5        6.1            3.2

Which of the choices below best describes how to measure the center of this data?

- Both centers are best described with the mean.

-Both centers are best described with the median.

- The Rome data center is best described by the mean. The New York data center is best described by the median.

-The Rome data center is best described by the median. The New York data center is best described by the mean.
Mathematics
2 answers:
Harrizon [31]2 years ago
5 0

Answer:  D. The Rome data center is best described by the median. The New York data center is best described by the mean.

I just completed the test and this is the correct answer. I apologize for no step by step explanation.

Gala2k [10]2 years ago
3 0

To solve this problem, let us first define what is mean and median. Mean is the average of all the numbers in the data set while the median is the number in the middle of the data set in ascending order.

If we create a box plot for the data of Rome and New York, we can see that there is an outlier in the data for New York. Since New York has an outlier, so the mean is not a good representation on the central tendency of the data. The mean is skewed (distorted) by the outlier. So in this case it is better to use the median.<span>

While the Rome data is nice and symmetrical, it does not seem to have an outlier,  so we can use the mean for this data set.</span>

 

Therefore the answer is:

<span>The Rome data center is best described by the mean. The New York data center is best described by the median</span>

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Find the first, fourth, and eighth terms of the sequence. A(n) = –3 • 2^n–1
Sphinxa [80]
A(n) = –3 • 2⁽ⁿ⁻¹⁾

for n = 1 ,  A₁ = -3.(2)⁰ = -3
for n = 2 ,  A₂ = -3.(2)¹ = -6
for n = 3 ,  A₃ = -3.(2)² = -12
for n = 4 ,  A₄ = -3.(2)³ = -24
...........................................
for n = 8 ,  A₈ = -3.(2)⁷ = -384


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2 years ago
After college graduation, Mario received employment offers from two companies. The first company offered a yearly salary of $31,
Alexandra [31]
The first thing we must do for this case is to define a variable:
 x: number of years
 y: total salary
 We have then:
 For first company:
 y = 1500x + 31000
 For second company:
 y = 2000x + 28500
 Equaling both equations we have:
 1500x + 31000 = 2000x + 28500
 Clearing x:
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 x = 2500/500
 x = 5
 Answer:
 
It will take for the salaries to be the same about:
 
x = 5 years
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2 years ago
Adam plans to choose a video game from a section of the store where everything is 75 % off . He writes the expression d - 0.75d
masha68 [24]

Answer:

Adam is taking the original price minus 75% of the original price, while Rena is taking the original price times 25% which is what you would be paying. Both are correct but Renas is more efficient.

Step-by-step explanation:


3 0
2 years ago
Read 2 more answers
A psychologist is collecting data on the time it takes to learn a certain task. For 50 randomly selected adult subjects, the sam
tatuchka [14]

Answer: (15.263,\ 17.537)

Step-by-step explanation:

According to the given information, we have

Sample size : n= 50

\overline{x}=16.40

s=4.00

Since population standard deviation is unknown, so we use t-test.

Critical value for  95 percent confidence interval  :

t_{n-1,\alpha/2}=t_{49, 0.025}= 2.009575\approx2.010

Confidence interval : \overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}

16.40\pm (2.010)\dfrac{4}{\sqrt{50}}\\\\=16.40\pm1.13702770415\\\\=16.40\pm1.1370\\\\=(16.40-1.1370,\ 16.40+1.1370)\\\\=(15.263,\ 17.537)

Required 95% confidence interval :  (15.263,\ 17.537)

8 0
2 years ago
1) Determine which events are mutually exclusive and which are not, when a single card is drawn from a deck. a. Getting a 7 and
Allisa [31]

Answer:

The events a) and c) are mutually exclusive.

Step-by-step explanation:

a) This is mutually exclusive, each card has a unique value between 2 and 10, or it is a jack, queen, king, or an Ace. A single card cant have two different values at the same time.

b) This is not mutually exclusive, since you can get a king of clubs. Each card can have any combination of one suit and one value.

c) A face card is either a Jack, a Queen or a King, it is not an Ace. For the same argument of a), a card cant have two different values, therefore this event is mutually exclusive.

d) This is not mutually exclusive, since a card can have any suit independently of the value it has (same argument than b), therefore, a card can be a face card and a spade at the exact time.

Therefore, events a and c are mutually exclusive.

7 0
2 years ago
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