D^2=x^2+y^2
d^2=(310+150cos20)^2+(150sin20)^2
d^2=205991.41373309
d=453.86mi
So C. to the nearest mile.
Answer:
Condition A.
A rectangle with four right angles
There can be many quadrilaterals satisfying this condition.
Condition B.
A square with one side measuring 5 inches
There can be only one quadrilateral satisfying this condition.
Condition C.
A rhombus with one angle measuring 43°
There can be many quadrilaterals satisfying this condition.
Condition D.
A parallelogram with one angle measuring 32°
There can be many quadrilaterals satisfying this condition.
Condition E.
A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.
There can be only one quadrilateral satisfying this condition.
Condition F.
A rectangle with adjacent sides measuring 4 inches and 3 inches.
There can be only one quadrilateral satisfying this condition
Step-by-step explanation:
If you have 20 square<span> pieces of wood, describe all the different ways you could make a rectangle by placing them side by side.</span><span>
1X20, 2X10, 4X5</span>
Answer:
3p*3p*3p*3p*3p*3p
Step-by-step explanation:
Multiply exponents
3p^6
expand
3p*3p*3p*3p*3p*3p = 3p^6
Let x be the number of hours of nagging groceries spent by Ethan. With this representation, the number of hours for moving lawns will be x + 10. The equation that would let us solve this item is,
6x + 7.50(x + 10) = 129
The value of x from the equation is 4. Thus, the number of hours spent for moving lawns is 14 hours.