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marta [7]
1 year ago
9

Let X denote the temperature (degree C) and let Y denote thetime in minutes that it takes for the diesel engine on anautomobile

to get ready to start. Assume that the joint density for(X,Y) is given by fxy (x,y) = c(4x + 2y +1) ; 0 < x< 40 and 0 < y <2.
(a) Find the value of c that makes this a density.
(b) Find the probability that on a randomly selected day theair temperature will exceed 20 degrees C and it will take at least1 minute for the car to be ready to start.
(c) Find the marginal densities for X and Y.
(d) Find the probability that on a randomly selected day itwill take at least one minute for the car to be ready tostart.
(e) Find the probability that on a randomly selected day theair temperature will exceed 20 degrees C.
(f) Are X and Y independent? Explain on mathematicallybasis.
Mathematics
1 answer:
BlackZzzverrR [31]1 year ago
4 0

Answer:

Step-by-step explanation:

Given f_{XY} (x,y) = c(4x + 2y +1) ; 0 < x < 40\,and\, 0 < y

a)

we know that \int\limits^\infty_{-\infty}\int\limits^\infty_{-\infty} {f(x,y)} \, dxdy=1

therefore \int\limits^{40}_{-0}\int\limits^2_{0} {c(4x+2y+1)} \, dxdy=1

on integrating we get

c=(1/6640)

b)

P(X>20, Y>=1)=\int\limits^{40}_{20}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

on doing the integration we get

                        =0.37349

c)

marginal density of X is

f(x)=\int\limits^2_{0} {\frca{1}{6640}(4x+2y+1)} \, dy

on doing integration we get

f(x)=(4x+3)/3320 ; 0<x<40

marginal density of Y is

f(y)=\int\limits^{40}_{0} {\frca{1}{6640}(4x+2y+1)} \, dx

on doing integration we get

f(y)=\frac{(y+40.5)}{83}

d)

P(01)=\int\limits^{40}_{0}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy

solve the above integration we get the answer

e)

P(X>20, 0

solve the above integration we get the answer

f)

Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.

we know f(x,y)

In the (c) bit we got f(x) and f(y)

f(x,y)cramster-equation-2006112927536330036287f(x).f(y)

therefore X and Y are not independent

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Sams annual college tuition will be $230 more than ryan's annual college tuition after sams college tuition increase by 10% next
Alik [6]

Answer:

Sounds like Sam better pull it together

Step-by-step explanation:

3 0
1 year ago
A direct variation function contains the points (-9, -3) and (-12,4). Which equation represents the function?
Triss [41]

Answer:

y = -\frac{7x}{3} - 24

Step-by-step explanation:

We can model this function using the equation of a line:

y = ax + b

Where a is the slope of the line and b is the y-intercept.

To find the values of a and b, we can use the two points given:

(-9, -3):

-3 = a * (-9) + b

-9a + b = -3

(-12, 4):

4 = a * (-12) + b

-12a + b = 4

If we subtract the second equation from the first one, we have:

-12a + b - (-9a + b) = 4 - (-3)

-12a + 9a = 4 + 3

-3a = 7

a = -7/3

Then, finding the value of b, we have:

-12a + b = 4

28 + b = 4

b = -24

So the equation is:

y = -\frac{7x}{3} - 24

3 0
1 year ago
Lavania is studying the growth of a population of fruit flies in her laboratory. After 6 days she had nine more than five times
MatroZZZ [7]

Answer:

Lavania observed 39 fruit flies after 6 days of observation

Step-by-step explanation:

Let x be the number of fruit flies on the first day of Lavania's study.

After 6 days she had nine more than five times as many fruit flies as when she began the study.

Five times as many fruit flies as when she began the study = 5x

Nine more than five times as many fruit flies as when she began the study=5x+9

The expression to find the population of fruit flies Lavania observed after 6 days is 5x+9

If she observes 20 fruit flies on the first day of the study, then x=6, then

5x+9=5\cdot 6+9=30+9=39

5 0
1 year ago
There were 340,000 cattle placed on feed. Write an equivalent ratio that could be used to find how many of these cattle were bet
lutik1710 [3]

There were 340,000 cattle placed on feed

How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?

Given the fraction of total cattle for 700 - 799 pounds is 2/5

Let x be the number of cattle between 700 - 799 pounds

We make a proportion using the fraction

\frac{2}{5} = \frac{x}{340,000}

Cross multiply it and solve for x

340000* 2 = 5x

680000 = 5x

Divide by 5 on both sides

So x= 136,000

There were 136,000 cattle between 700 and 799 pounds

3 0
1 year ago
Read 2 more answers
Use deductive reasoning to show that the following procedure always produces the number 6. Procedure: Pick a number. Add 4 to th
Flauer [41]

Answer:

procedure always produces 6

Step-by-step explanation:

Let 'n' be the unknown number

Add 4 to the number : n+4

multiply the sum by 3.

multiply the sum n+4 by 3

3(n+4) is 3n+12

Now subtract 6, so we subtract 6 from 3n+12

3n+12-6=3n+6

finally decrease the difference by the tripe of the original number

triple of original number is 3n

3n+6-3n= 6

so the procedure always produces 6

5 0
1 year ago
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