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Alexxx [7]
2 years ago
15

The velocity of an object in meters per second varies directly with time in seconds since the object was dropped, as represented

by the table.
A two column table with 6 rows. The first column has, Time in seconds, and has the entries, 0, 1, 2, 3, 4. The second column, Velocity in meters per second, has the entries, 0, 9.8, 19.6, 29.4, 39.2.
The acceleration due to gravity is the constant of variation. What is the acceleration due to gravity of a falling object?

4.9 9.8 StartFraction m Over s squared EndFraction.
9.8 9.8 StartFraction m Over s squared EndFraction.
10.2 10.2 StartFraction m Over s squared EndFraction.
19.6 19.6 StartFraction m Over s squared EndFraction.
Mathematics
2 answers:
poizon [28]2 years ago
6 0

Answer:

B

Step-by-step explanation:

edg2021

lana [24]2 years ago
6 0

Answer:

The answer is B

Step-by-step explanation:

Edge2021

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In the derivation of the quadratic formula by completing the square, the equation (x+b over 2a)^2=-4ac+b^2 over 4a^2 is created
vredina [299]

Answer:

The result of applying the square root property of equality to this equation is x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}.

Step-by-step explanation:

Consider the provided equation.

\left(x+\dfrac{b}{2a}\right)^2=\dfrac{-4ac+b^2}{4a^2}

As the above equation is formed by perfect square trinomial so simply applying the square root property as shown:

\sqrt{(x+\dfrac{b}{2a})^2}=\pm \dfrac{\sqrt{-4ac+b^2}}{\sqrt{4a^2}}\\x+\dfrac{b}{2a}=\pm \dfrac{\sqrt{b^2-4ac}}{2a}

Isolate the variable x.

x=-\dfrac{b}{2a}\pm \dfrac{\sqrt{b^2-4ac}}{2a}\\x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Hence, the result of applying the square root property of equality to this equation is x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}.

4 0
1 year ago
Read 2 more answers
​(c) if the corresponding terms of two arithmetic sequences are​ added, is the resulting sequence​ arithmetic?
Harman [31]

To determine whether the corresponding terms of 2 arithmetic sequence's added will give new arithmetic sequence or not, Let' take 2 Arithmetic sequences.

In one first term is a1 and common difference is d1, in the other first term is a2 and common difference is d2.

Now nth term for first sequence = a1+(n-1) d1

  nth term for second sequence = a2+(n-1) d2

Now add the 2 terms: a1+(n-1)d1 +a2 +(n-1)d2

                                   = a1+a2 + (n-1)(d1+d2)

This is again new arithmetic sequence with first term a1+a2 and common difference d1+d2.

Hence if we add corresponding terms of 2 arithmetic sequence, we will again get an arithmetic sequence.

5 0
1 year ago
You buy a new television for $3,100. The value of the television decreases by 12 percent every year. How much is the television
IrinaK [193]

Answer:

is this wht u r searching for.....

6 0
1 year ago
Read 2 more answers
In a data set with a range of 55.4 to 105.4 and 400 observations, there are 176 observations with values less than 86. Find the
IrinaVladis [17]

<u>ANSWER: </u>

In a data set with a range of 55.4 to 105.4 and 400 observations.86 lies in the 49th percentile.

<u>SOLUTION: </u>

Given, in a data set with a range of 55.4 to 105.4 and 400 observations.

There are 176 observations below the value of 86, and we need to find the percentile for 86.

We know that, percentile formula = \frac{\text {number of observations below the required number}}{\text {total number of observations}} \times 100

Percentile of 86 = \frac{176}{400} \times 100

Since, we cancelled 400 with 100 we get 4 , hence above expression becomes,

=\frac{176}{4} = 49

So, percentile of 86 = 49

Hence, 86 lies in the 49th percentile.  

5 0
2 years ago
Ann is grouping 38 rocks. She can put them into groups of 10 rocks or as single rocks. What are the different ways Ann can group
hoa [83]

Answer: There will be two different ways of doing so.

Step-by-step explanation:

Since we have given that

Total number of rocks =38

If we want to groups of 10 rocks or as single rocks then there are 2 different ways ;

<u>Case I:</u>

if we group into 10 rocks

there will be four sets in which Ist set contains 10 rocks

Second set contains 10 rocks

Third set contains 10 rocks

and Fourth set remains with 8 rocks only.

<u>Case II:</u>

if we group as single rocks .

There will be 38 sets .



7 0
1 year ago
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