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Ne4ueva [31]
2 years ago
15

Select all of the following true statements if R = real numbers, Z = integers, and W = {0, 1, 2, ...}.

Mathematics
2 answers:
goblinko [34]2 years ago
4 0

Answer:

W ⊂ Z: TRUE. As mentioned earlier, Z includes all whole numbers thus W is a subset of it.

R ⊂ W: FALSE. Not all real numbers are whole numbers. Whole numbers must be rational and expressed without fractions. Some real numbers do not meet this criteria.

0 ∈ Z: TRUE. Zero is indeed an integer thus it is an element of Z.

∅ ⊂ R: TRUE. A null set is a subset of R, and in fact every set in general. There are no elements in a null set thus making it automatically a subset of any non-empty set by definition (since NONE of its elements are not an element of R).

{0,1,2,...} ⊆ W: TRUE. The set on the left is exactly what is defined on the problem statement for W. (The bar below the subset symbol just means that the subset is not strict, therefore the set on the left can be equal to the set on the right. Without it, the statement would be false since a strict subset requires that the two sets should not be equal).

-2 ∈ W: FALSE. W is just composed of whole numbers and not of its negated counterparts.

Step-by-step explanation:

PSYCHO15rus [73]2 years ago
3 0
We can start solving this problem by first identifying what the elements of the sets really are.

R is composed of real numbers. This means that all numbers, whether rational or not, are included in this set.

Z is composed of integers. Integers include all negative and positive numbers as well as zero (it is essentially a set of whole numbers as well as their negated values).

W on the other hand has 0,1,2, and onward as its elements. These numbers are known as whole numbers.

W ⊂ Z: TRUE. As mentioned earlier, Z includes all whole numbers thus W is a subset of it.

R ⊂ W: FALSE. Not all real numbers are whole numbers. Whole numbers must be rational and expressed without fractions. Some real numbers do not meet this criteria.

0 ∈ Z: TRUE. Zero is indeed an integer thus it is an element of Z.

∅ ⊂ R: TRUE. A null set is a subset of R, and in fact every set in general. There are no elements in a null set thus making it automatically a subset of any non-empty set by definition (since NONE of its elements are <u>not</u> an element of R).

{0,1,2,...} ⊆ W: TRUE. The set on the left is exactly what is defined on the problem statement for W. (The bar below the subset symbol just means that the subset is not strict, therefore the set on the left can be <u>equal</u> to the set on the right. Without it, the statement would be false since a strict subset requires that the two sets should not be equal).

-2 ∈ W: FALSE. W is just composed of whole numbers and not of its negated counterparts.
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Freddy the frog is climbing up a well. Every day he climbs up 3 m but some nights he falls asleep and slips back 4m at the start
Anarel [89]

Answer: The frog fell asleep for 4 nights.

Step-by-step explanation: First, he climbs up 3m every night. there are 16 nights before he gets to 29m. He has not climbed up for the 16th day so 15*3= 45. 45-29= 16. 16/4=4. The frog slept for 4 nights.

7 0
2 years ago
The stem-and-leaf plot below shows the number of pages each student in the class read the previous evening. A stem and leaf plot
Tatiana [17]

Answer:

75% students read less than 35 pages.

Step-by-step explanation:

The stem and leaf plot is given below

0    |   5   0   5   8  

1     |   2   3   5   8   8   9

2    |   2   4   6   7   7   7

3    |   3   5   6

4    |   2   4   6

5    |   7

Count the students in each row.

Row 1 = 4 students

Row 2 = 6 students

Row 3 = 6 students

Row 4 = 3 students

Row 5 = 3 students

Row 6 = 1 student

Total students = 23 students

75% of 23 students = 0.75/100 · 23 = 12.25 students

75% of 23 students ≅ 17 students

From the stem and leaf plot, 17th student read 33 pages while 18th student reads 35 pages.

Which means

75% students read less than or equal to 33 pages.

OR

75% students read less than 35 pages

6 0
2 years ago
Read 2 more answers
A jet flying at 123 m/s banks to make a horizontal circular turn. The radius of the turn is 3810 m, and the mass of the jet is 2
aev [14]

Answer:

The magnitude of the necessary lifting force is 7.95N

Step-by-step explanation:

Force = mv^2/r

mass (m) = 2.00105kg, velocity (v) = 123m/s, radius (r) = 3810m

Force = 2.00105×123^2/3810 = 30273.89/3810 = 7.95N

7 0
2 years ago
1. Dennis made a 500 km trip in five hours. For the first two hours, Dennis had an average speed of 150 km/h. For the last two h
Sati [7]

Answer:

The correct option is;

Dennis must have stopped for an hour in the middle of this trip

Step-by-step explanation:

The given parameters are;

The distance Dennis covered in 5 hours = 500 km

Dennis's average speed in the first two hours = 150 km/h

Dennis's average speed in the last two hours = 100 km/h

Therefore;

Dennis traveled 150 km/h × 2 h = 300 km in the first two hours

Dennis traveled 100 km/h × 2 h = 200 km in the last two hours

Which gives, Dennis traveled 300 km + 200 km in  2h + 2h = 4h

Therefore, Dennis traveled 500 km in 4 hours and Dennis must have stopped for an hour in the middle of this trip.

6 0
2 years ago
Hadley paddled a canoe 2/3 mile in 1/4 hour. How fast did Hadley paddle in miles per hour ?
Vitek1552 [10]

Answer:2 2/3 miles per hour

Step-by-step explanation:to get one mile you multiply 1/4 by 4 and to keep 1/4 and 2/3 proportional you also have to multiply 2/3 by 4

5 0
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