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kobusy [5.1K]
2 years ago
13

If a debt of $480 is reduced by 20% find the new debt

Mathematics
1 answer:
Marina86 [1]2 years ago
3 0
10% = 480$ / 10
= 48$
20% = 48$ * 2
= 96$

480$ - 96$ = 384$
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Sasha is bisecting a segment. First, she places the compass on one endpoint, opens it to a width larger than half of the segment
FrozenT [24]

Answer:

A) Swing arcs on both sides to intersect the first two arcs created.

Step-by-step explanation:

Bisecting a segment is cutting a line into two equal parts with a line bisector.

The steps involved are;

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  • Opening the compass to a width larger than half of the segment
  • Swinging an arc on either side of the segment
  • While maintaining the same width, place the compass on the other endpoint
  • Swing arcs on both sides of the segment to intersect the first two arcs created
  • Using a ruler placed at the points of intersection of the arcs, draw the line bisector.

Sasha was now at step four.

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You've decided to take 3 steps and randomly choose left or right as the direction each time.
Montano1993 [528]

Answer:

i would say b

Step-by-step explanation:

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2 years ago
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Find the value of x in each case:
Zanzabum

Answer:

x=30\°

Step-by-step explanation:

<u>Find the measures of interior angles in each triangle</u>

Triangle BGC

m

The measures of triangle BGC are 90\°-60\°-30\°

Triangle CGH

we know that

m -----> by consecutive interior angles

we have that

m

so

m

m

substitute

m

we have

m

m

m

remember that

m

60\°+2x+180\°-4x=180\°

60\°=2x

x=30\°

The measures of triangle CGH are 60\°-60\°-60\°

Triangle GHE

m< EGH=90\°-2x=90-2(30\°)=30\°

m< GHE=4x=4(30\°)=120\°

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m

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30\°+120\°+m

150\°+m

m

The measures of triangle GHE are 30\°-120\°-30\°

6 0
2 years ago
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Find the average value of the function f(x, y, z) = 5x2z 5y2z over the region enclosed by the paraboloid z = 4 − x2 − y2 and the
S_A_V [24]
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin. 

<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>

<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>

<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>

<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>


<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>

<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>

<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>

<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>

<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
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2 years ago
The water was pumped out of a backyard pond. what is the domain of this graph
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Water was pumped out in t-hours.
Time t would be the domain, 0 to t.
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