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sasho [114]
1 year ago
14

write five numbers that are at least 8 digits long under standard form write the expanded form and the word form for each number

under the appropriate heading
Mathematics
2 answers:
ozzi1 year ago
7 0
45,886,903
Expanded Form : 40,000,000+ 5,000,000+
800,000+80,000+6,000+900+3
Word Form:forty five million eight hundred eighty six thousand nine hundred and three
11,111,111
10,000,000+1,000,000+100,000+10,000+1,000+100+10+1
eleven million one hundred eleven thousand and one hundred eleven
12,345,678
10,000,000+2,000,000+300,000+40,000+5,000+600+70+8
twelve million three hundred forty five thousand and six hundred seventy eight
24,680,135
20,000,000+4,000,000+
600,000+80,000+100+30+5
twenty four million six hundred eighty one hundred thirty five
74,914,475
70,000,000+4,000,000+900,000+10,000+4,000+400+70+5
frosja888 [35]1 year ago
3 0
12,568,983
10,000,000+2,000,000+500,000+60,000+
8,000+900+80+3
Twelve million five hundred sixty-eight thousand nine hundred eighty-three

99,999,999
90,000,000+9,000,000+900,000+90,000+9,000+900+90+9
Ninety-nine million nine hundred ninety-nine thousand nine hundred ninety-nine

12,345,678
10,000,000+2,000,000+300,000+40,000+
5,000+600+70+8
Twelve million three hundred forty-five thousand six hundred seventy-eight

49,275,546
40,000,000+9,000,000+200,000+70,000+5,000+500+40+6
Forty-nine million two hundred seventy-five thousand five hundred forty-six

64,834,174
60,000,000+4,000,000+800,000+30,000+4,000+100+70+4
Sixty-four million eight hundred thirty-four thousand one hundred seventy-four

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Answer:

Step-by-step explanation:

Total cost for the three nights

Total_3 = $298.17 + 3*u

Where <em>u </em>represents the unknown fees for a single day

To find the daily cost, we divide the previous equation by three

Daily cost = ($298.17 + 3*u)/3

Daily cost = ($99.39 + u)

So, if we create an inequality for the daily cost

Let x = Daily cost

x > $99.39

She will pay more than $99.39 per night

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2 years ago
A rectangle’s length is 2 units more than twice its width. Its area is 40 square units. The equation w(2w + 2) = 40 can be used
barxatty [35]
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Solve the equation 4x2 + 2 = 38 using square roots.
hammer [34]

Answer:

Step-by-step explanation:

Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations 4x^2-2=38 so that you ... Step 2 : Step 3 :Pulling out like terms. 3.1 Pull out like factors : 4x2 - 40 = 4 • (x2 - 10) ... x2 = 10. When two things are equal, their square roots are equal.

3 0
1 year ago
Uche pumps gasoline at a rate of 18\,\dfrac{\text{L}}{\text{min}}18 min L ​ 18, start fraction, start text, L, end text, divided
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Answer:

Uche's pumping rate is <u>300 mL/s</u>.

Step-by-step explanation:

Given:

Uche pumps gasoline at a rate of 18 L/min.

Now, to find Uche's pumping rate in mL/s.

The rate at which Uche pumps gasoline = 18 L/min.

So, to get the pumping rate in mL/s we use convert L/min to mL/s by using conversion factor:

<u>1 L/min = 16.6667 mL/s.</u>

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1 year ago
Let Y denote a geometric random variable with probability of success p. a Show that for a positive integer a, P(Y &gt; a) = qa .
lakkis [162]

Answer:

a) For this case we can find the cumulative distribution function first:

F(k) = P(Y \leq k) = \sum_{k'=1}^k P(Y =k')= \sum_{k'=1}^k p(1-p)^{k'-1}= 1-(1-p)^k

So then by the complement rule we have this:

P(Y>a) = 1-F(a)= 1- [1-(1-p)^a]= 1-1 +(1-p)^a = (1-p)^a = q^a

b) P(Y>a)= q^a

P(Y>b) = q^b

So then we have this using independence:

P(Y> a+b) = q^{a+b}

We want to find the following probability:

P(Y> a+b |Y>a)

Using the definition of conditional probability we got:

P(Y> a+b |Y>a)= \frac{P(Y> a+b \cap Y>a)}{P(Y>a)} = \frac{P(Y>a+b)}{P(Y>a)} = \frac{q^{a+b}}{q^a} = q^b = P(Y>b)

And we see that if a = 2 and b=5 we have:

P(Y> 2+5 | Y>2) = P(Y>5)

c) For this case we use independent identical and with the same distribution experiments.

And the result for part b makes sense since we are interest in find the probability that the random variable of interest would be higher than an specified value given another condition with a value lower or equal.

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

If we define the random of variable Y we know that:

Y\sim Geo (1-p)

Part a

For this case we can find the cumulative distribution function first:

F(k) = P(Y \leq k) = \sum_{k'=1}^k P(Y =k')= \sum_{k'=1}^k p(1-p)^{k'-1}= 1-(1-p)^k

So then by the complement rule we have this:

P(Y>a) = 1-F(a)= 1- [1-(1-p)^a]= 1-1 +(1-p)^a = (1-p)^a = q^a

Part b

For this case we can use the result from part a to conclude that:

P(Y>a)= q^a

P(Y>b) = q^b

So then we have this assuming independence:

P(Y> a+b) = q^{a+b}

We want to find the following probability:

P(Y> a+b |Y>a)

Using the definition of conditional probability we got:

P(Y> a+b |Y>a)= \frac{P(Y> a+b \cap Y>a)}{P(Y>a)} = \frac{P(Y>a+b)}{P(Y>a)} = \frac{q^{a+b}}{q^a} = q^b = P(Y>b)

And we see that if a = 2 and b=5 we have:

P(Y> 2+5 | Y>2) = P(Y>5)

Part c

For this case we use independent identical and with the same distribution experiments.

And the result for part b makes sense since we are interest in find the probability that the random variable of interest would be higher than an specified value given another condition with a value lower or equal.

8 0
2 years ago
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