Answers:
A) △ACF ≅ △AEB because of ASA.
D) ∠CFA ≅ ∠EBA
E) FC ≅ BE
Solution:
AC ≅ AE; ∠ACD ≅ ∠AED Given
The angle ∠CAF ≅ ∠EAB, because is the same angle in Vertex A
Then △ACF ≅ △AEB because of ASA (Angle Side Angle): They have a congruent side (AC ≅ AE) and the two adjacent angles to this side are congruent too (∠ACD ≅ ∠AED and ∠CAF ≅ ∠EAB), then option A) is true: △ACF ≅ △AEB because of ASA.
If the two triangles are congruent, the ∠CFA ≅ ∠EBA; and FC ≅ BE, by CPCTC (Corresponding Parts of Congruent Triangles are Congruent), then Options D) ∠CFA ≅ ∠EBA and E) FC ≅ BE are true
Answer:
-10
Step-by-step explanation:
30m - 22m =80 therefore m is equal to -10
To determine the maximum value of a quadratic function opening downwards, we are going to find the vertex; then the y-value of the vertex will be our maximum.
To find the vertex (h,k) (where h=x-coordinate and k=y-coordinate) of a quadratic function of the form

we'll use the vertex formula:

, and then we are going to replace that value in our original function to find k.
So, in our function

,

and

.
Lets replace those values in our vertex formula:



Now that we know the x-coordinate of our vertex, lets replace it in the original function, to get the y-coordinate:



We just prove that the vertex of

is (2,1), and for the graph we can tell that the vertex of

is (-2,4). The only thing left is compare their y-coordinates to determine w<span>hich one has the greater maximum value. Since 4>1, we can conclude that </span>

has the greater maximum.