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Maurinko [17]
2 years ago
8

AC ≅ AE; ∠ACD ≅ ∠AED

Mathematics
2 answers:
lana66690 [7]2 years ago
6 0
On online learning  its A,D,E
pshichka [43]2 years ago
4 0

Answers:

A) △ACF ≅ △AEB because of ASA.

D) ∠CFA ≅ ∠EBA

E) FC ≅ BE


Solution:

AC ≅ AE; ∠ACD ≅ ∠AED Given

The angle ∠CAF ≅ ∠EAB, because is the same angle in Vertex A

Then △ACF ≅ △AEB because of ASA (Angle Side Angle): They have a congruent side (AC ≅ AE) and the two adjacent angles to this side are congruent too (∠ACD ≅ ∠AED and ∠CAF ≅ ∠EAB), then  option A)  is true: △ACF ≅ △AEB because of ASA.

If the two triangles are congruent, the ∠CFA ≅ ∠EBA; and FC ≅ BE, by CPCTC (Corresponding Parts of Congruent Triangles are Congruent), then Options D) ∠CFA ≅ ∠EBA and E) FC ≅ BE are true

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Answer:

a) 2nd container is more efficient and contains the elements for a container.

b) The cylinder has a........A)Smaller surface area B)bigger C)equal

And will cost.....A)Less to produce B)more C)The same

Step-by-step explanation:

a) The 2nd container has these elements:

Width 20.5cm

Length 6.5cm

side 3.25cm

So, the volume in cubic cm is 20.5 x 6.5 x 3.25 = 433cm3.

This container can hold the 300cm3 of juice.

b) A cylinder is a geometric solid common in everyday life.  Examples of a cylinder are soup cans, food tins, drink cans, candles, toilet paper rolls, cups, aerosol cans, flower vases, test tubes, fire extinguishers, plant containers, salt shakers and pencil holders.  The two ends are called bases, and are usually circular.  Though, they can take other shapes.  When a cylinder is unrolled and flattened out, the side is actually a rectangle.

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Eighty percent of one store's customers paid with credit cards. Forty customers came in that day. How many customers paid for th
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a recipe calls for 3 ounces of flour for every 2 ounces of sugar. Find the constant of proportionality.
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for every 3 ounces of flour, you need 2 ounces of sugar
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For an outdoor track meet to be cancelled, the temperature, t, outside must be colder than 35 degrees. Complete the following in
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a(0.3−y)+1.1+2.4x (y−1.2) ​ =0 =−1.2(x−0.5) ​ Consider the system of equations above, where aaa is a constant. For which value o
Veseljchak [2.6K]

Answer:

For a = 1.22 there is one solution where y = 1.3

Step-by-step explanation:

Hi there!

Let´s write the system of equations:

a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0

-1.2(x-0.5) = 0

Let´s solve the second equation for x:

-1.2(x-0.5) = 0

x- 0.5 = 0

x = 0.5

Now let´s repalce x = 0.5 and y = 1.3 in the first equation and solve it for a:

a(0.3 - y) + 1.1 +2.4x(y-1.2) = 0

a(0.3 - 1.3) + 1.1 + 2.4(0.5)(1.3 -1.2) = 0

a(-1) + 1.1 + 1.2(0.1) = 0

-a + 1.22 = 0

-a = -1.22

a = 1.22

Let´s check the solution and solve the system of equations with a = 1.22. Let´s solve the first equation for y:

1.22(0.3 - y) + 1.1 +2.4(0.5)(y-1.2) = 0

0.366 - 1.22y + 1.1 + 1.2 y - 1.44 = 0

-0.02y +0.026 = 0

-0.02y = -0.026

y = -0.026 / -0.02

y = 1.3

Then, the answer is correct.

Have a nice day!

4 0
2 years ago
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