There were 340,000 cattle placed on feed
How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?
Given the fraction of total cattle for 700 - 799 pounds is 2/5
Let x be the number of cattle between 700 - 799 pounds
We make a proportion using the fraction
Cross multiply it and solve for x
340000* 2 = 5x
680000 = 5x
Divide by 5 on both sides
So x= 136,000
There were 136,000 cattle between 700 and 799 pounds
<h3>
✽ - - - - - - - - - - - - - - - ~<u>
Hello There</u>
!~ - - - - - - - - - - - - - - - ✽</h3>
➷ a/sinA = c/sinC
Substitute in the values:
37/sin(42) = c/sin(41.5)
Multiply both sides by sin(41.5)
37/sin(42) x sin(41.5) = c
Solve:
c = 36.63999457
The correct answer would be C. 36.64
<h3><u>
✽</u></h3>
➶ Hope This Helps You!
➶ Good Luck (:
➶ Have A Great Day ^-^
↬ ʜᴀɴɴᴀʜ ♡
30 gallons * 5 = 150 gallons
3 quarts * 5 = 15 quarts
1 pint * 5 = 5 pints
Four quarts in a gallon: 15/4 = 3 gallons, 2 quarts
2 pints in a quart: 5/2 = 2 quarts, 1 pint
2 quarts + 2 quarts = 1 gallon
150 + 3 + 1 gallons + 1 pint = 153 gallons, 1 pint.
Answer:
see below
Step-by-step explanation:
12.5x − 10.2 = 3(2.5x + 4.2) - 6
Use the distributive property to distribute the 3
12.5x − 10.2 = 7.5x + 12.6 − 6
Combine like terms
12.5x − 10.2 = 7.5x + 6.6
Add 10.2 to each side of the equation by using the addition property of equality
12.5x = 7.5x + 16.8
Subtraction 7.5x from each side of the equation by using the subtraction property of equality
5x = 16.8
Divide by 5 on each side by using the division property of equality
x = 3.36
