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2 years ago

A submarine submerged at a depth of -32.25 meters dives an additional 8.5 meters. What is he new depth of the submarine?

Mathematics

2 answers:

kvasek [131]2 years ago

3 0

-40.75 meters is the answer

777dan777 [17]2 years ago

3 0

Answer:

New depth = -40.75 meters

Step-by-step explanation:

It should be understood that submersion is a physical process in which height is lost, so that as there is more submersion there is less height, that is, height and submersion are inversely proportional.

When talking about a submersion depth of -32.25 meters, that means the submarine has dropped 32.25 meters.

If we add 8.5 meters of additional submersion to that value, we get ....

-32.25 meters + (-8.5 meters) = -32.25 meters - 8.5 meters = -40.75 meters.

In other words, we have ...

Initial Depth = -32.25 meters

Additional depth = -8.5 meters

New depth = -40.75 meters

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I hope this helps!

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Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

Whose textbook reaches the ground first and by how many seconds?

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

2 years ago

The production department has installed a new spray machine to paint automobile doors. As is common with most spray guns, unsigh

Nesterboy [21]

Answer:

The numbers of doors that will have no blemishes will be about 6065 doors

Step-by-step explanation:

Let the number of counts by the worker of each blemishes on the door be (X)

The distribution of blemishes followed the Poisson distribution with parameter $\lambda =0.5$ / door

The probability mass function on of a poisson distribution Is:

$P(X=x) = \dfrac{e^{- \lambda } \lambda ^x}{x!}$

$P(X=x) = \dfrac{e^{- \ 0.5 }( 0.5)^ x}{x!}$

The probability that no blemishes occur is :

$P(X=0) = \dfrac{e^{- \ 0.5 }( 0.5)^ 0}{0!}$

$P(X=0) = 0.60653$

P(X=0) = 0.6065

Assume the number of paints on the door by q = 10000

Hence; the number of doors that have no blemishes is = qp

=10,000(0.6065)

= 6065

3 0

2 years ago

Two sides of an obtuse triangle measure 9 inches and 14 inches. The length of longest side is unknown. What is the smallest poss

julia-pushkina [17]

Answer:

17 inches

Step-by-step explanation:

An obtuse triangle is the triangle in which one of the side is the longest. It contains an obtuse angle and the longest side is the side that is opposite to the vertex of the obtuse angle.

Let the three sides of the obtuse triangle be a, b and c respectively with c as the longest side. Let a = 9 inches and b = 14 inches.

Now we know that for an obtuse triangle,

$c^2 > a^2 +b^2$

$c^2 > (9)^2 +(14)^2$

$c^2 > 81 +196$

$c^2 > 277$

c > 16.64

Therefore the smallest possible whole number is 17 inches.

4 0

1 year ago

Read 2 more answers

In △ABC,c=71, m∠B=123°, and a=65. Find b. A. 101.5 B. 117.8 C. 123.0 D. 119.6

tia_tia [17]

Answer:

Option D

Step-by-step explanation:

The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the two sides that are given are adjacent to each other the given angle is the included angle. This means that the angle B is formed by the intersection of the lines a and c. Therefore, cosine rule will be used to calculate the length of b. The cosine rule is:

b^2 = a^2 + c^2 - 2*a*c*cos(B).

The question specifies that c=71, B=123°, and a=65. Plugging in the values:

b^2 = 65^2 + 71^2 - 2(65)(71)*cos(123°).

Simplifying gives:

b^2 = 14293.0182932.

Taking square root on the both sides gives b = 119.6 (rounded to the one decimal place).

This means that the Option D is the correct choice!!!

8 0

2 years ago

Billy Jo's school is selling tickets to a Fall Festival. On the first day of ticket sales the school sold 3 adult ticket and 8 s

denis23 [38]

Answer:

Y = 6

Step-by-step explanation:

On the first day of ticket sales the school sold 3 adult ticket and 8 student tickets for a total of $72. The school took in $152 on the second day by selling 7 adult tickets and 16 student tickets. How much is a student ticket?

Day 1: 3x + 7y = 72

Day 2: 7x + 16y = 152

This becomes a system of equations.

3x+8y=72

3x+8y+−8y=72+−8y (Add -8y to both sides)

3x=−8y+72

3x/3 = −(8y+72)/3

X = (-8/3) y + 24

Substitute (-8/3) y + 24 for x in7x+16y=152:

7(-8/3 y + 24) + 16y = 152

-8/3 y + 168 = 152 (Simplify both sides of the equation)

-8/3 y + 168 − 168 = 152 + (−168) (Add -168 to both sides)

-8/3 y = -16

(-8/3 y)/(-8/3 y) = -16/ -8/3 y (Divide both sides by (-8)/3)

y = 6

If you wanted to keep going...

Substitute 6f or y in x = (-8/3) y + 24

(-8/3) y + 24 = (-8/3) (6) + 24

SImplify: x = 8

X = 8 and Y = 6

Hope this helps! ♥

~A.W.E.S.W.A.N~

6 0

2 years ago