M=slope
In this case the slope would be $25
y=mx+b
y=25x+45
Answer: m=25
Fifty Nine And Thirty Plus Twenty Nine
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature =
= 15°c
The final temperature =
= 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × (
-
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
B. The total area painted is 864; they must buy two cans of paint.
Step-by-step explanation:
Step 1:
A rectangle's area can be calculated by multiplying its length and its width. The wall is made up of 5 different types of rectangular walls. All walls are 8 feet tall but the length varies.
Step 2:
The area of the 20 feet long wall = 
The area of the 10 feet long wall = 
The area of the 5 feet long wall = 
The area of the 4 feet long wall = 
The area of the 15 feet long wall = 
The area of all the walls = 432 square feet.
Since there are two sides for every wall, total area =
square feet.
Step 3:
If one paint can covers 500 square feet,
the number of cans required to paint 864 square feet =
cans.
so 2 paint cans are needed to paint 864 square feet which is option B.