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shusha [124]
2 years ago
14

Two quadratic functions are represented below.

Mathematics
2 answers:
Tpy6a [65]2 years ago
7 0
To determine the maximum value of a quadratic function opening downwards, we are going to find the vertex; then the y-value of the vertex will be our maximum.
To find the vertex (h,k) (where h=x-coordinate and k=y-coordinate) of a quadratic function of the form f(x)=a x^{2} +bx+c we'll use the vertex formula: h= \frac{-b}{2a}, and then we are going to replace that value in our original function to find k.

So, in our function f(x)=- x^{2} +4x-3, a=-1 and b=4. 
Lets replace those values in our vertex formula:
h= \frac{-4}{2(-1)}
h= \frac{-4}{-2}
h=2

Now that we know the x-coordinate of our vertex, lets replace it in the original function, to get the y-coordinate:
h=f(2)=-(2^{2} )+4(2)-3
h=-4+8-3
h=1

We just prove that the vertex of f(x) is (2,1), and for the graph we can tell that the vertex of g(x) is (-2,4). The only thing left is compare their y-coordinates to determine w<span>hich one has the greater maximum value. Since 4>1, we can conclude that </span>g(x) has the greater maximum.
pantera1 [17]2 years ago
3 0

1) The first way is graphing. You can find the maximum value visually by graphing the equation and finding the maximum point on the graph

2) The second way to determine the maximum value is using the equation y = ax² + bx + c.

If your equation is in the form ax² + bx + c, you can find the maximum by using the equation:

max/min = c - (b2 / 4a).

The first step is to determine whether your equation gives a maximum or minimum. This can be done by looking at the x² term. 

If x²>0------------ > the vertex point will be a minimum. 

If x²<0-------------> the vertex will be a maximum.

3)There's one more way to determine the maximum value of a function, and that is from the equation:

y = a(x - h)2 + k

<span>If the a term in this equation must be negative for there to be a maximum. </span>

<span>If the a term is negative, the maximum can be found at k. No equation or calculation is necessary - the answer is just k.</span>

<span>
</span>

using a graph tool

see the attached figure


the maximum value of f(x) is 1 at the point (2,1)

the maximum value of g(x) is 4 at the point (-2,4)

the answer is 

<span>The function g(x) has the greater maximum value</span>

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The solutions to the linear differential equation d2u/dt2 = u form a vector space (since combinations of solutions are still sol
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Serious high school. This is one of the few differential equations I can solve.

The usual particular solution is u=e^t because e^t is its own derivative.

An independent solution is u=e^{-t} which has a negative sign in the first derivative which turns back to positive in the second.

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But we only are asked for the basis.

Answer:\textrm{. } \quad e^t, \quad e^{-t}


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​mars, inc. claims that​ 20% of its​ m&amp;m plain candies are orange. a sample of 100 such candies is randomly selected. find t
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4 0
2 years ago
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