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NikAS [45]
2 years ago
11

terry sees this offer. refurbished phone 35%off now only £78. how much was the phone before the discountes price?

Mathematics
1 answer:
borishaifa [10]2 years ago
6 0

Answer:

the price now  is 100-35=65% of the initial price p

65p/100=78

65p=78*100

p=7800/65

p=120 ( the phone before the discounted price )

Step-by-step explanation:

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Ellie buys a mobile phone in spain for €352.50. Her brother jack buys an identical phone from japan for ¥39856. Using exchange r
Nonamiya [84]

Answer:

The answer to your question is: Japan

Step-by-step explanation:

Mobile cost in Spain = € 352.5

Mobile cost in Japan = ¥39856

Exchange rate = £1 = €1.41

                           £1 = ¥188

Cost of mobile in pounds

                       £ 1 ------------------ € 1.41

                        x  -----------------   €352.5

                       x = (352.5 x 1) / 1.41

                       x= £250

                      £1   ------------------  ¥188

                      x    ----------------- -¥ 39856

                     x = (39856 x 1) / 188

                     x = £212

Then, it was cheaper in Japan

8 0
1 year ago
Read 2 more answers
The center of a circle is located at (3, 8), and the circle has a radius that is 5 units long. What is the general form of the e
inna [77]

Answer:

The general equation of a circle is x² + y² - 6x - 16y + 48 = 0 .

Step-by-step explanation:

The standard form of equation of circle.

(x - h)^{2} + (y - k)^{2} = r^{2}

Where (h,k) is the centre of a circle and r is the radius.

As given

The center of a circle is located at (3, 8), and the circle has a radius that is 5 units .

Put in the formula

(x - 3)^{2} + (y - 8)^{2} = 5^{2}

(By using the formula (a - b)² = a² + b²- 2ab)

As 5² = 25

x² + 9 - 6x + y² + 64 - 16y = 25

x² + y² - 6x - 16y + 9 + 64 = 25

x² + y² - 6x - 16y + 73 = 25

x² + y² - 6x - 16y + 73 - 25 = 0

x² + y² - 6x - 16y + 73 - 25 = 0

x² + y² - 6x - 16y + 48 = 0

(As the general equation of a circle are in the form x² + y² + Ax +By + F =0   Where A,B and C are constant .)

Therefore the general equation of a circle is x² + y² - 6x - 16y + 48 = 0 .

6 0
1 year ago
Two processes are used to produce forgings used in an aircraft wing assembly. Of 200 forgings selected from process 1, 10 do not
tangare [24]

Answer:

a.

\bar p_1=0.05\\\bar p_2=0.067

b-Check illustration  below

c.(-0.0517,0.0177

Step-by-step explanation:

a.let p_1  \& p_2 denote processes 1 & 2.

For p_1: T1=10,n1=200

For p_2:T2=20,n2=300

Therefore

\bar p_1=\frac{t_1}{N_1}=\frac{10}{200}=0.05\\\bar p_2=\frac{t_2}{N_2}=\frac{20}{300}=0.067

b. To test for hypothesis:-

i.

H_0:p_1=p_2\\H_A=p_1\neq p_2\\\alpha=0.05

ii.For a two sample Proportion test

Z=\frac{\bar p_1-\bar p_2}{\sqrt(\bar p(1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})}\\

iii. for \frac{\alpha}{2}=(-1.96,+1.96) (0.5 alpha IS 0.025),

reject H_o if|Z|>1.96

iv. Do not reject H_o. The noncomforting proportions are not significantly different as calculated below:

z=\frac{0.050-0.067}{\sqrt {(0.06\times0.94)\times \frac{1}{500}}}

z=-0.78

c.(1-\alpha).100\% for the p1-p2 is given as:

(\bar p_1-\bar p_2)\pm Z_0_._5_\alpha \times \sqrt   \frac{ \bar p_1(1-\bar p_1)}{n_1}+\frac{\bar p_2(1-\bar p_2)}{n_2}\\\\=(0.05-0.067)\pm 1.645  \times \sqrt \ \frac{0.05+0.95}{200}+\frac{0.067+0.933}{300}\\

=(-0.0517,+0.0177)

*CI contains o, which implies that proportions are NOT significantly different.

4 0
2 years ago
Petra is shopping with 2 of her friends. She buys a note book and six identical pencils. The note book costs the same as 2 of th
max2010maxim [7]

Answer: £4.20

Each 2 of pencils is £4.20 multiply that by 3 your get 12.60, the notebook is the same price of 2 pencils so that must mean it is £4.20

4.20 x 4 = 16.80

3 £4.2 from the 6 pencils

and 1 £4.2 from the notebook

Hope this helps!

3 0
2 years ago
If PQ and RS intersect to form four right angles which statement is true
Rus_ich [418]
Given that PQ and RS intersect to form four right angles, then they form an angle of 90 degrees, this implies that:
if the meet at point O, 
then;
∠POR=∠POS=∠QOS=∠ROQ=90°
Therefore the correct statement is:
PQ is perpendicular to RS
that is to mean:
PQ⊥RS
The answer is C.
7 0
1 year ago
Read 2 more answers
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