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1 year ago

The slope of a line is 2. The y-intercept of the line is –6. Which statements accurately describe how to graph the function?

2 answers:

7 0

A because (0,-6) is the y-intercept so you start at the point you know. Then because slope is a rise over run fraction the slope can also be written as 2/1 which is rise 2 over 1.

Semenov [28]1 year ago

4 0

Answer:

A is the correct option.

Step-by-step explanation:

The slope of the line is 2 and the y-intercept is -6.

y-intercept is the point where x is zero. Hence, the point is (0,-6)

When we graph a linear function by slope-intercept method, first of all we plot the y-intercept.

Hence, first of all we plot the point (0,-6)

Now, slope is given by

$\text{slope}=\frac{rise}{run}$

if rise is positive then we move up from the y -intercept and if negative then move down. We keep run always positive and hence we move right from the rise point.

$\text{slope}=2=\frac{rise}{run}$

rise = 2

run = 1

Rise is positive hence, we move 2 units up from the point (0,-6) and then move 1 unit right to get the next point. Then we draw a line passing through these points.

A is the correct option.

You might be interested in

In a GP if T3 = 18 and T6 = 486 Find:- T10

mote1985 [20]

Answer:

The 10th term of the G.P is 29.

Step-by-step explanation:

Given : In a GP if $T_3=18$ and $T_6 = 486$ .

To find : The term $T_{10}$ ?

Solution :

The geometric sequence is in the form, $a,ar,ar^2,ar^3,...$

Where, a is the first term and r is the common ratio.

The nth term of G.P is $T_n=ar^{n-1}$

We have given, $T_3=18$

i.e. $T_3=ar^{3-1}$

$18=ar^{2}$ ....(1)

$T_6 = 486$

i.e. $a_6=ar^{6-1}$

$486=ar^{5}$ ....(2)

Solving (1) and (2) by dividing them,

$\frac{486}{18}=\frac{ar^{5}}{ar^{2}}$

$27=r^3$

$r=\sqrt[3]{27}$

$r=3$

Substitute in (1),

$18=a(3)^{2}$

$18=9a$

$a=2$

The first term is a=2 and the common ratio is r=3.

The 10th term, of GP is given by,

$T_{10}=2+(10-1)3$

$T_{10}=2+(9)3$

$T_{10}=2+27$

$T_{10}=29$

Therefore, The 10th term of the G.P is 29.

8 0

1 year ago

Read 2 more answers

If e^(xy) = 2, then what is dy/dx at the point (1, ln2)

PSYCHO15rus [73]

By implicit differentiation:

(x(dy/dx) + y)e^(xy) = 0 

Note that when differentiating e^(xy), apply chain rule. When differentiating xy, use product rule. Also: When differentiating y w/respect to x, think of that as if you are differentiating f(x). 

Then, substitute (1,ln(2)) and solve for dy/dx. 

(1(dy/dx) + ln(2))e^(1ln(2)) = 0 
((dy/dx) + ln(2))e^(ln(2)) = 0 

Note that e^(ln(2)) = 2 since e and ln are inverse of each other. 

2((dy/dx) + ln(2)) = 0 
dy/dx + ln(2) = 0 . . . . You get this expression by dividing both sides by 2 
dy/dx = -ln(2) . . . . . . .Subtract both sides by ln(2) 

Therefore, dy/dx = -ln(2) 

I hope this helps!

8 0

1 year ago

In 2.5 hours, Mr. Castelli drives a distance of 125 miles. He wants to know his average driving speed in meters per minute. Comp

xeze [42]

Okay. So we'll start off by talking about miles per hour. Me. Castelli drove 125 miles in 2.5 hours. Divide 125 and 2.5 hours and you see that he drove 50 miles (81 kilometers) in one hour. 1,000 meters are in 1 meter, and 1,000 * 81 = 81,000. So he drives 81,000 meters in 1 hour. To find meters per minute, you divide 81,000 by 60, and you'll get 1,350 meters per minute. Here it is written for you to understand it better:
Miles per hour: 50
Kilometers per hour: 81
Meters per hour: 81,000
Meters per minute: 1,350

3 0

2 years ago

Bruce wants to make 50 ml of an alcohol solution with a 12% concentration. He has a 10% alcohol solution and a 15% alcohol solut

wel

(50 - x) is the amount of the 15% Alcohol solution to use. If you solve for x first.
0.10x + 0.15(50 – x) = 0.12(50)
0.10x - 0.15x + 7.5 = 6
-0.05x + 7.5 = 6
7.5 - 6 = 0.05x
1.5 = 0.05x
1.5/0.05 = x
30 mL = x

Then the 15% solution: 50 - 30 = 20 mL

7 0

1 year ago

Read 2 more answers

A neighborhood is trying to set up school carpools, but they need to determine the number of students that need to travel to the

katrin [286]

Answer:

The correct option is 1.

Step-by-step explanation:

From the given histogram it is clear that

In age group 5-10, the number of students is 7.

In age group 11-13, the number of students is 5.

In age group 14-18, the number of students is 4.

It means age of 7 students lie in the interval 5-10, age of 5 students lie in the interval 11-13 and age of 4 students lie in the interval 14-18.

Total number of elements in the data set is $7+5+4=16$

In option 3 and 4 number of elements is data set is less than 16. So, option 3 and 4 are incorrect.

In option 2 all the data set lie in the interval 5-10. So, option 2 is incorrect.

In option 1,

Class intervals elements frequency

5-10 5,6,7,8,9,10,10 7

11-13 11,11,12,12,13 5

14-18 14,14,15,16 4

From the above table we can conclude that data set 1 represented in the given histogram.

Therefore the correct option is 1.

4 0

2 years ago

Read 2 more answers