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Illusion [34]
1 year ago
11

Help with maths question please

Mathematics
1 answer:
mars1129 [50]1 year ago
6 0
<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Substitute -3 into g(x)

g(-3) = 2(-3) + 4

Solve:

g(x) = -2

Substitute this value into f(x)

f(-2) = 3(-2)^2

Solve:

f(-2) = 12

The answer is B. 12

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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Two groups of students were asked how many pets they had. The table below shows the numbers for each group:
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where are the answers?
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1 year ago
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A botanist collected one leaf at random from each of 10 randomly selected mature maple trees of the same species. The mean and t
Zarrin [17]

Answer:

One sample t-test for population mean would be the most appropriate method.

Step-by-step explanation:

Following is the data which botanist collected and can use:

  • Sample mean
  • Sample Standard Deviation
  • Sample size (Which is 10)
  • Distribution is normal

We have to find the best approach to construct the confidence interval for one-sample population mean. Two tests are used for constructing the confidence interval for one-sample population mean. These are:

  • One-sample z test for population mean
  • One-sample t test for population mean

One sample z test is used when the distribution is normal and the population standard deviation is known to us. One sample t test is used when the distribution is normal, population standard deviation is unknown and sample standard deviation is known.

Considering the data botanist collected, One-sample t test would be the most appropriate method as we have all the required data for this test. Using any other test will result in flawed intervals and hence flawed conclusions.

Therefore, One-sample t-test for population mean would be the most appropriate method.

8 0
2 years ago
The following histogram represents the distribution of acceptance rates (percent accepted) among 25 business schools in 2004. In
Mila [183]

Answer:

  • <u><em>Option b. just below 30%</em></u>

<u><em></em></u>

Explanation:

Please, see attached the <em>histogram that represents the distribution of acceptance rates (percent accepted) among 25 business schools in 2004. </em>

<em />

The<em> median</em> is the value that separates the lower 50% from the upper 50% of the data.

Since there are 25 business schools, the middle value is the number 13.

The height of each bar is the<em> frequency</em> or number of business school for that acceptace rate:

  • The first bar has frequency of 1 school
  • The second bar has frequency of 3 schools: cummulative frequency: 1+3=4.
  • The third bar has frequency 5 schools: cummulative frequency 4 + 5 = 9.
  • The fourth bar has frequency 3 schools: cummulative frequency: 9+3=12.

Then, the 13th value is on the next bar, the fifth bar.

The fifth bar has acceptance rates 25  ≤ rate < 30.

That means that the median acceptance rate is greater than or equal to 25 and less than 30.

Thus, the choice is the option <em>b. just below 30%.</em>

3 0
1 year ago
Tania has 56 liters of milk. She uses the milk to make muffins and cakes. Each batch of muffin requires 7 liters of milk and eac
mihalych1998 [28]
Write the inequalities that are given by the :

<span>x: the number of batches of muffins

y: the number of batches of cakes

</span>Each batch of muffin requires 7 liters of milk and each batch of cakes require 4 liters of milk.

=> liters of milk use = 7x  + 4y

<span>Tania has 56 liters of milk.=> 7x + 4y ≤ 56

Which means that the amount of muffins and cakes made are limited by the availability of 56 liter of milk.

The inequality 7x + 4y ≤ 56 is graphed by drawing the line 7x + 4y = 56 and shading the region below that line.

The line 7x + 4y = 56 has these x and y intercepts:

y-intercept: x =0 => 4y = 56 => y = 56/4 => 14 => point (0,14)

x-intercept => y = 0 => 7x = 56 => x = 56/7= 8  => point (8,0)

So, the line passes through the poins (0,8) and (14,0) and the solution region is below that line.

Also, you know that x and y are restricted to be positive or zero =>

x ≥ 0

y ≥ 0.

So, the solution region is restricted to the first quadrant.

That implies that the answer is:
</span><span>
Line joining ordered pairs 0, 14 and 8, 0. Shade the portion of the graph below this line which lies within the first quadrant
</span>


4 0
2 years ago
Please answer all of them need this
VikaD [51]

First Question

For a better understanding of the solution provided here please find the first attached file which has the diagram of the the isosceles trapezoid.

We dropped perpendiculars from C and D to intersect AB at Q and P respectively.

As can be seen in \Delta BCQ, we can easily find the values of CQ and BQ.

Since, Sin(75^0)=\frac{CQ}{8}

\therefore CQ=8\times Sin(75^0)\approx 7.73 ft

In a similar manner we can find BQ as:

Cos(75^0)=\frac{BQ}{8}

BQ\approx2.07 ft

All these values can be found in the diagram attached.

Thus, because of the inherent symmetry of the isosceles trapezoid, PQ can be found as:

PQ=22-(AP+QB)=22-(2.07+2.07)=17.86

Let us now consider\Delta AQC

We can apply the Pythagorean Theorem here to find the length of the diagonal AC which is the hypotenuse of \Delta AQC.

AC=\sqrt{(AQ)^2+(QC)^2}=\sqrt{(AP+PQ)^2+(QC)^2}=\sqrt{(2.07+17.86)^2+(7.73)^2}\approx21.38 feet.

Thus, out of the given options, Option B is the closest and hence is the answer.

Second Question

For this question we can directly apply the formula for the area of a triangle using sines which is as:

Area=\frac{1}{2}(First Side)(Second Side)(Sine of the angle between the two sides)

Thus, from the given data,

Area=\frac{1}{2}\times 218.5\times 224.5\times sin(58.2^0)\approx20845 m^2

Therefore, Option D is the correct option.

Third Question

For this question we will apply the Sine Rule to the \Delta ABC given to us.

Thus, from the triangle we will have:

\frac{AB}{Sin(\angle C)}=\frac{BC}{Sin(\angle A)}

\frac{c}{Sin(\angle C)}=\frac{a}{Sin(\angle A)}

\frac{17}{Sin(25^0)}=\frac{a}{Sin(45^0)}

This gives a to be:

a\approx28.44

Which is not close to any of the given options.

Fourth Question

Please find the second attachment for a better understanding of the solution provided her.

As can be clearly seen from the attached diagram, we can apply the Cosine Rule here to find the return distance of the plane which is CA.

AC=\sqrt{(AB)^2+(BC)^2-2(AB)(BC)\times Cos(\angle B)}

\therefore AC=\sqrt{(172.20)^2+(111.64)^2-2(172.20)(111.64)\times Cos(177.29^0)}\approx283.8 miles.

Thus, Option D is the answer.





8 0
2 years ago
Read 2 more answers
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