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1 year ago

Explain two different squares that can be made using the number 9

1 answer:

3 0

One square can be a 3 by 3 square, meaning each side is 3 units.The area for this would be 9.

Another one is the square can be a 9 by 9 square, meaning each side is 9 units. The area for this would be 81.

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To determine what students at a school would be willing to do to help address global warming, researchers take a random sample o

erastovalidia [21]

Answer:

(ai) The correct answer is the first option; The amount of tax the student is willing to add to a gallon of gasoline.

(aii) The correct answer is the last option; Whether the student believes that global warming is a serious issue or not.

(b) The correct answer is the first option; two-sample t interval

Step-by-step explanation:

A response variable in statistics is the idea or concept of needs to be proven right or wrong. It remains a response variable until it has been proven.

An explanatory variable simply means an independent variable. It doesn't depend on any other variable and at the same time, it can be manipulated.

In construct a 95% confidence interval to compare the two groups, two-sample t test is the appropriate t test to use.

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1 year ago

Which expression is equivalent to mc003-1.jpg?

Nookie1986 [14]

Answer:

Option A is correct

The expression which is equivalent to $(f\cdot g)(5)$ is $f(5) \cdot g(5)$

Step-by-step explanation:

Using the formula:

$(f \cdot g)(x) = f(x) \cdot g(x)$ .....[1]

Given the expression:

$(f\cdot g)(5)$

Substitute the value of x = 5 in [1]

we get;

$(f \cdot g)(5) = f(5) \cdot g(5)$

Therefore, the expression which is equivalent to $(f\cdot g)(5)$ is $f(5) \cdot g(5)$

8 0

2 years ago

Read 2 more answers

What types of concurrent constructions are needed to find the orthocenter of a triangle? A. intersection of the lines drawn perp

finlep [7]

Answer: Hello! The answer to your question is B, the intersection of the lines drawn to bisect each vertex of the triangle. Hope this helped! Please pick my answer as the Brainliest!

4 0

1 year ago

During April of 2013, Gallup randomly surveyed 500 adults in the US, and 47% said that they were happy, and without a lot of str

Brilliant_brown [7]

Answer:

number of successes

$k = 235$

number of failure

$y = 265$

The criteria are met

The sample proportion is $\r p = 0.47$

$E =4.4 \%$

What this mean is that for N number of times the survey is carried out that the which sample proportion obtain will differ from the true population proportion will not more than 4.4%

$r = 0.514 = 51.4 \%$

$v = 0.426 = 42.6 \%$

This 95% confidence interval mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit is 95%

Given that 50% of the population proportion lie with the 95% confidence interval the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

Yes our result would support the claim because

$\frac{1}{3 } \ of N < \frac{1}{2} (50\%) \ of \ N , \ Where\ N \ is \ the \ population\ size$

Step-by-step explanation:

From the question we are told that

The sample size is $n = 500$

The sample proportion is $\r p = 0.47$

Generally the number of successes is mathematical represented as

$k = n * \r p$

substituting values

$k = 500 * 0.47$

$k = 235$

Generally the number of failure is mathematical represented as

$y = n * (1 -\r p )$

substituting values

$y = 500 * (1 - 0.47 )$

$y = 265$

for approximate normality for a confidence interval criteria to be satisfied

$np > 5 \ and \ n(1- p ) \ >5$

Given that the above is true for this survey then we can say that the criteria are met

Given that the confidence level is 95% then the level of confidence is mathematically evaluated as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha =0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table, the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{ \frac{\r p (1- \r p}{n} }$

substituting values

$E = 1.96 * \sqrt{ \frac{0.47 (1- 0.47}{500} }$

$E = 0.044$

=> $E =4.4 \%$

What this mean is that for N number of times the survey is carried out that the proportion obtain will differ from the true population proportion of those that are happy by more than 4.4%

The 95% confidence interval is mathematically represented as

$\r p - E < p < \r p + E$

substituting values

$0.47 - 0.044 < p < 0.47 + 0.044$

$0.426 < p < 0.514$

The upper limit of the 95% confidence interval is $r = 0.514 = 51.4 \%$

The lower limit of the 95% confidence interval is $v = 0.426 = 42.6 \%$

This 95% confidence interval mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit is 95%

Given that 50% of the population proportion lie with the 95% confidence interval the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

Yes our result would support the claim because

$\frac{1}{3 } < \frac{1}{2} (50\%)$

3 0

1 year ago

Jordan prepares 200 name tags to use at a meeting. The number for each color of the name tag is described below.

nadya68 [22]

Answer:

The answer would be A. 55.

Step-by-step explanation:

For the 35% you would take your 200 and divide it by 2 and have two 100's. Since 35% is out of 100% you could take 35 from each 100 and add them together to get 70.

For the 3/8 you would divide and get .375 then you would multiply that by 200 which would give you 75 yellow tags. Then you would add 75 and 70 and get 145. Then subtract 145 from 200 to get 55. Therefore there would be 55 red tags.

5 0

1 year ago