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Gnesinka [82]
2 years ago
14

The length of a river is 480 km. What is its length on a map with a scale 1:5,000,000?

Mathematics
2 answers:
NeX [460]2 years ago
8 0

Answer:

PLEASE MARK BRAINLIEST

the answer is 9.6 cm

Step-by-step explanation:

Greeley [361]2 years ago
6 0

Answer:

The length of the river on a map is 9.6\ cm

Step-by-step explanation:

we know that

The scale of the map is 1:5,000,000

That means

1 cm on a map is 5,000,000 cm on the actual

or

1 cm on a map is 50 km cm on the actual

so

using proportion

\frac{1}{50}\frac{cm}{km}=\frac{x}{480}\frac{cm}{km}\\ \\x=480/50\\ \\x=9.6\ cm

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The figure below shows the ideal pattern of movement of a herd of cattle, with the arrows showing the movement of the handler as
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Answer:

  109.9 ft

Step-by-step explanation:

The length of an arc that is 1/4 of a circle of radius 70 ft is ...

  s = rθ

  s = (70 ft)(π/2) = 35π ft ≈ 109.9557 ft

The best answer choice appears to be 109.9 feet.

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2 years ago
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Which of the following sets of ordered pairs represents a function?
joja [24]
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2 years ago
The measures in the table describe the weights of animals that visited a vet on one day, in pounds. Mean Median Mode Mean Absolu
MrMuchimi

Answer: On average, the weight of a pet visiting this vet on this day is about 2.4 pounds away from 12.9 pounds.

If the MAD of weights for another day was 1.5, then that day's weights would be less variable than the weights of pets seen on this day.

Step-by-step explanation:

Given: The measures in the table describe the weights of animals that visited a vet on one day, in pounds.

Mean = 12.9

Median= 12.0

Mode = 12.0

Mean Absolute Deviation = 2.4

We know that the mean absolute deviation (MAD) of a data set is the mean distance between each and every data value and the mean.It tells about the variation in a data set.

Therefore, On average, the weight of a pet visiting this vet on this day is about 2.4 pounds away from 12.9 pounds.

Also, If the MAD of weights for another day was 1.5, and since 1.5< 2.4.

Then that day's weights would be less variable than the weights of pets seen on this day.

8 0
2 years ago
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A movie streaming website charges an initial fee of $50, plus $5 for each movie that is streamed. How many movies must be stream
alukav5142 [94]
The average cost of streaming N movies will be
.. average cost = (total cost)/(number of movies)
.. = (50 +5N)/N
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4 0
1 year ago
A scientist who studies teenage behavior was interested in determining if teenagers spend more time playing computer games then
Marina86 [1]

Answer:

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Step-by-step explanation:

Given information:

mean, X = 10.2 hours

sample, n = 15

using t distribution

test statistics = 2.822

P_{value} = 2 x P(t_{n-1} > test statistics)

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P_{value} is less than 0.10 which indicates that the amount of time greater than 10.2 hours for this year.

5 0
2 years ago
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