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photoshop1234 [79]
2 years ago
10

A basketball team has eight boys and four girls on the roster. The boys average 12 points each. The team averages 136 points as

a whole. How many points does each girl average?
Mathematics
2 answers:
lorasvet [3.4K]2 years ago
4 0

8 x 12 = 96

136-96 =40

40/4 = 10

 each girl averages 10 points

klasskru [66]2 years ago
4 0
The girls average about 10 points a game
the boys have 8 player 
EX. 12x8=96 
136-96=40
There are four girls so 40 is divided evenly so the answer is 10 points a game
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I subtract 14 from a certain number I multiply the result by 3 the final answer is 3 what was the number
12345 [234]

Answer:

15.

Step-by-step explanation:

3(x - 14) = 3

3x - 42 = 3

3x = 42 + 3 = 45

x = 15.

3 0
2 years ago
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HELP WILL GIVE BRAINLIEST!!Aiden has $15.00 on his copy card. Each time he uses the card to make a photocopy, $0.06 is deducted
diamong [38]

Answer:

166

Step-by-step explanation:

$15.00-$5.00= $10.00 (subtract five dollars because aiden wants to have at least five dollars left)

10.00 divided by 0.06=  166

I hope this helps! :)

3 0
1 year ago
If e = 9 cm and f = 40 cm, what is the length of g?
rewona [7]

(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.

Answer: D. 41 cm

There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,

a^2+b^2 = (b+1)^2

a^2 + b^2 = b^2 + 2b +1

a^2=2b+1

So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.

b = (a^2 - 1)/2

a=3, b=(3^2-1)/2=4, c=b+1=5

a=5, b=(5^2-1)/2 =12, c = 13

a=7, b=24, c=25

a=9, b=40, c=41

a=11, b=60, c=61

a=13, b=84, c=85

It's good to be able to recognize Pythagorean Triples when we see them.  

Otherwise we'd have to work the calculator:

√(9² + 40²) = √1681 = 41

8 0
2 years ago
Which expression is equivalent to b^-2/ab^-3 assume a=0 b=0
andrey2020 [161]
B^-2/ab^-3 = b^-2/b^-3 x 1/a = b^[-2-(-3)] x 1/a = b x 1/a = b/a
3 0
2 years ago
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A candy store sells caramels and milk chocolate by the pound the table below shows the total cost in dollars for a pound of each
MakcuM [25]

The cost of 1\frac{3}{4} pounds chocolate milk is $6.25 more than the cost of 1\frac{3}{4} pounds of Caramel.

Step-by-step explanation:

Given,

Cost of one pound of Caramels = $10.28

Cost of 1\frac{3}{4} pounds of Caramel = 10.28*1\frac{3}{4}

Cost of 1\frac{3}{4} pounds = 10.28*\frac{7}{4}=\frac{71.96}{4}= \$17.99

Cost of one pound of chocolate milk = $13.85

Cost of 1\frac{3}{4} pounds = 13.85*1\frac{3}{4}=13.85*\frac{7}{4}

Cost of 1\frac{3}{4} pounds = \frac{96.95}{4}=\$24.24

Difference = 24.24 - 17.99 = $6.25

The cost of 1\frac{3}{4} pounds chocolate milk is $6.25 more than the cost of 1\frac{3}{4} pounds of Caramel.

Keywords: difference, multiplication

Learn more about multiplication at:

  • brainly.com/question/10414011
  • brainly.com/question/10483199

#LearnwithBrainly

5 0
2 years ago
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