In order to construct this equation, we will use the variables:
V to represent mixture volume (40 ml)
C to represent mixture concentration (0.32)
v₁ to represent volume of first solution (40 / 4 = 10 ml)
c₁ to represent concentration of first solution (0.2)
v₂ to represent the volume of the second solution (40 * 3/4 = 30 ml)
c₂ to represent the concentration of the second solution
We know that the total amount of substance, product of the volume and concentration, in the final solution is equal to the individual amounts in the two given solutions. Thus:
VC = v₁c₁ + v₂c₂
40(0.32) = 10(0.2) + 30c
We have the expression:
3x(x-12x) + 3x^2 - 2(x-2)^2
First, we will expand the power 2 bracket as follows:
3x(x-12x) + 3x^2 - 2(x^2 - 4x +4)
Then, we will get rid of the brackets as follows:
3x^2 - 36x^2 + 3x^2 - 2x^2 + 8x - 8
Now, we will gather the like terms and add them as follows:
-32 x^2 + 8x - 8
We can take the 8 as a common factor:
8 ( -4x^2 + x -1)
Given:
10 blue marbles ; 15 yellow marbles, 5 green marbles, 6 red marbles
A total of 36 marbles.
Probabilities:
1st marble: red = 6/36
2nd marble: yellow = 15/35
6/36 * 15/35 = 6*15 / 36*35 = 90/1260 = 1/14
The probability that Kendra will draw a red marble and then a yellow marble is 1/14.
Answer:
736 N
Step-by-step explanation:
The dimensions of the rectangular tile are:
Length = 2.3m
Width = 1.6m
The pressure exerted on a surface is given by the formula
where
p is the pressure
F is the force exerted
A is the area on which the force is exerted
In this problem, we have:
is the maximum pressure that the tile is able to sustain
A is the area of the tile, which can be calculated as the product between length and width, so:
Re-arranging the formula for F, we can find the maximum force that can be safely applied to the tile:
