Answer:
Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)
Step-by-step explanation:
Given: Probability of a children under age 5 has food allergies = 7%
=
To find : Probability of atleast one of 12 student has food allergies
Probability of a chindren under age 5 does not have food allergies = 
⇒ prob = 
now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.
But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)
Probability of 0 student having allergy out of 12 student = 
Therefore, Probability of atleast one of 12 student has food allergies
= 
= 
≈ 0.58 ( approx)
Answer:
the monthly rents of the apartments
Step-by-step explanation:
In the field of statistics, the population of interest may be defined as the group or the population from which the experimenter or the researcher tries to make conclusions or draw their results.
In the context, I am interested to study the cost of the rented house that is more than others in the West Campus area.
So I recorded the monthly rents of the apartments from a sample of 30 one bedroom apartments.
Therefore, the population of interest for my study here is the monthly rents recorded from the sample of one bedroom apartments.
Let the score of cowboys is x
and giants make score 9 which is twice less than the cowboys score so
giants score will be = 2x -9
and packers scored 14 more than giants that is (2x - 9) + 14
now sum of their scores is equal to 81 it means:
x + (2x - 9) + (2x -9) + 14 = 81
x + 2x - 9 + 2x - 9 + 14 = 81
5x = 81 + 4
5x = 85
x = 17
packers scored = (2x - 9) + 14
= 2 (17) -9 + 14
=38 + 5 = 43 points
X+x=15 combine like terms on left side
2x=15 divide both sides by 2
x=7.5
Consider two triangles AEB and CEF. In these triangles:
- ∠AEB≅∠CEF (as vertical angles);
- ∠EAB≅∠ECF (lines AB and CD are parallel and AC is transversal, then these angles are congruent as alternate interior angles);
- ∠ABE≅∠CFE (lines AB and CD are parallel, BF is transversal, then these angles congruent as alternate interior angles).
Thus, by AAA theorem, 
Corresponding sides of similar triangles are proportional, then
ABCD is a parallelogram, then AB=CD.
Therefore,
CD=2CF and CD=DF+CF. Equate these two expressions:
DF+CF=2CF,
DF=CF.
This gives you that DF:CF=1:1.
Answer: 1:1
